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3 years ago

Which of the following forces can change the motion of an object? A. push B. shove C. pull D. all of these

Physics

1 answer:

Goshia [24]3 years ago

3 0

Answer: The answer is D all of these sorry if i am wrong

Explanation:

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Two small objects are suspended from threads. When the objects are moved close together, they attract one another. What of the f

creativ13 [48]

Answer:d

Explanation:

All the given situations are possible because

(a)When particles are oppositely charged then they attract each other

(b)One is Positively charged and other is uncharged: Charged particle will induce charges of opposite nature to attract the other particle

(c)Negatively charged particles will induce the positive charge in the uncharged particle to attract the initially uncharged particle.

4 0

3 years ago

A particle's position is given by z(t) = −(6.50 m/s2)t2k for t ≥ 0. (Express your answer in vector form.) a. Find the particle's

blondinia [14]

Answer:

a) $z'(t) =v(t) = -13t$

Now we can replace the velocity for t=1.75 s

$v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}$

For t = 3.0 s we have:

$v(3.0s) = -13*3.0 =-39 \frac{m}{s}$

b) $v_{avg}= \frac{z_f - z_i}{t_f -t_i}$

And we can find the positions for the two times required like this:

$z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m$

$z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m$

And now we can replace and we got:

$V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}$

Explanation:

The particle position is given by:

$z(t) = -(6.5 \frac{m}{s^2}) t^2, t\geq 0$

Part a

In order to find the velocity we need to take the first derivate for the position function like this:

$z'(t) =v(t) = -13t$

Now we can replace the velocity for t=1.75 s

$v(1.75s) = -13*1.75 =-22.75 \frac{m}{s}$

For t = 3.0 s we have:

$v(3.0s) = -13*3.0 =-39 \frac{m}{s}$

Part b

For this case we can find the average velocity with the following formula:

$v_{avg}= \frac{z_f - z_i}{t_f -t_i}$

And we can find the positions for the two times required like this:

$z_f = z(3.0s) = -(6.5 \frac{m}{s^2}) (3.0s)^2=-58.5m$

$z_i = z(1.75s) = -(6.5 \frac{m}{s^2}) (1.75s)^2=-19.906m$

And now we can replace and we got:

$V_{avg}= \frac{-58.5 -(-19.906) m}{3-1.75 s}= -30.875 \frac{m}{s}$

8 0

3 years ago

Order the sequence of ideas that led to Marie Curie’s discovery of radioactive elements. Number the events in chronological orde

Marysya12 [62]

Answer:

2 1 3

Explanation:

6 0

3 years ago

Two forces of magnitudes 5 N and 8 N act on a body. What are the maximum and minimum resultant forces that can act on the body?

Ivan

Answer:

Max. = 13 N

Mjn. = 3 N

Explanation:

Max. resultant will be when these forces are being applied in the same direction(along the same line), we'll simply sum up the forces to get the resultant in this case.

= 5 + 8

= 13 N

Min. resultant will be when these forces are being applied in opposite directions (the forces must be present along the same line).

We'll subtract them to get the resultant now

= 8 - 5

= 3 N

3 0

3 years ago

A double star has two components of equal brightness, each with a magnitude of 8.34. if these stars are so close together that t

lesya692 [45]

Assuming that the magnitude is additive, then you simply have to add the brightness four times. This is because each star has 2 magnitudes of 8.34. As a result, you have to add 4 magnitudes of 8.34. The solution is as follows:

Magnitude = 4(8.34)
Magnitude = 33.36

7 0

3 years ago