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2 years ago

Provide an explanation tok please 80 points!!

Physics

1 answer:

nalin [4]2 years ago

8 0

Answer:

4th answer

Explanation:

have a good rest of ur day

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A dentist’s drill starts from rest. After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min. Find the

mylen [45]

Answer:

Angular acceleration, is $708.07\ rad/s^2$

Explanation:

Given that,

Initial speed of the drill, $\omega_i=0$

After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed, $\omega_f=28940\ rev/min=3030.58\ rad/s$

We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.

$\alpha =\dfrac{\omega_f}{t}\\\\\alpha =\dfrac{3030.58\ rad/s}{4.28\ s}\\\\\alpha =708.07\ rad/s^2$

So, the drill's angular acceleration is $708.07\ rad/s^2$ .

4 0

2 years ago

A 64.0 kg pole vaulter running at 10.2 m/s vaults over the bar. If the vaulter's horizontal component of velocity over the bar i

Lubov Fominskaja [6]

Answer:

h = 5.05 m

Explanation:

given,

mass of pole vaulter, m = 64 Kg

speed of the vaulter,V = 10.2 m/s

horizontal component of velocity in air, v = 1 m/s

height of the jump,h = ?

using energy conservation

$E_i = E_f$

$\dfrac{1}{2}mv_i^2 + m g h_i= \dfrac{1}{2}mv_f^2+m g h_f$

initial height of the vaulter is equal to zero.

$\dfrac{1}{2}v_i^2 = \dfrac{1}{2}v_f^2+gh_f$

$h =\dfrac{v_i^2-v_f^2}{2g}$

$h =\dfrac{10^2-1^2}{2\times 9.8}$

h = 5.05 m

height of the jump is equal to 5.05 m.

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3 years ago

Pls help with this problem, it's not too hard

ehidna [41]

Answer:

.25 Hz

Explanation:

Period = 4 sec

freq = 1/p = 1/4 hz = .25 Hz

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2 years ago

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sweet [91]

Answer:

Area

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permetivity

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According to a rule-of-thumb, each five seconds between a lightning flash and the following thunder gives the distance to the fl

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3 years ago