Answer:
AC)=(AB)2+(BC)2−−−−−−−−−−−−√=42+32−−−−−−√
⇒displacement=16+9−−−−−√=25−−√=5m
The power developed is 500 W ( to the nearest Watt)
Power(P) is the rate at which work is done. Work done (W) is the product of the force applied on the object and the displacement (s) made by the point of application of the force.
Therefore,
Substitute the given values of force , displacement and time
Thus the Power can be rounded off to the nearest value of 500 W
Hooke's Law states that the extension is directly proportional to the force applied so:
F/x = constant
F₁/x₁ = F₂/x₂
2 / 0.02 = 1600 / x₂
x₂ = 16 m
Elastic work = 1/2 Fx
= 1/2 * 1600 * 16
= 12.8 kJ
Q=mc(t2-t1)
Q=2.06kg x specific heat of oil(191-23)
Q=2.06×c×168
Q=143.62q
Answer:
The index refraction of the unknown material is 1.08
Explanation:
Light has characteristics of a wave. When light travels or propagates through two media with different index of refraction, the light will bend or will change its speed.
Using Snells' law which is stated mathematically as:
n1Sintheta1 = n2Sinthetha2
Given:
n1 = 1.17
Theta1 = 40.1° = angle of incidence
Theta2 = 36.3° = angle of refraction
n2 = unknown
Substituting into the equation
n1Sin40.1 = 1.17Sin36.3°
0.6441n1 = 0.6937
n1 = 0.6937/0.6441
n1 = 1.08
