Answer:
Option C.
Impulse = mass × change in velocity
Explanation:
Impulse is defined by the following the following formula:
Impulse = force (F) × time (t)
Impulse = Ft
From Newton's second law of motion,
Force = change in momentum /time
Cross multiply
Force × time = change in momentum
Recall:
Impulse = Force × time
Thus,
Impulse = change in momentum
Recall:
Momentum = mass x velocity
Momentum = mv
Chang in momentum = mass × change in velocity
Change in momentum = mΔv
Thus,
Impulse = change in momentum
Impulse = mass × change in velocity
Answer:
F=1.65 x 10²⁶ N
Explanation:
Given that
Distance ,R= 3.34 x 10¹² m
Mass m₁= 2.78 x 10³⁰ kg
Mass ,m₂= 9.94 x 10³⁰ kg
we know that gravitational force F given as
G=Constant
G=6.67 x 10⁻¹¹ Nm²/kg²
Now by putting the values
F=1.65 x 10²⁶ N
Therefore the force between these two mass will be 1.65 x 10²⁶ N.
Answer:
KE + PE = KE + PE
Explanation:
In a closed system, the mechanical energy of the system is constant.
Mechanical energy is given by the sum of kinetic energy and potential energy; mathematically:
U = KE + PE
where
KE is the kinetic energy
PE is the potential energy
This means that if we consider two situations, one at the beginning and one at the end, the value of U will not change if the system is closed; this means that the sum KE + PE will remain the same, so we can write:
KE + PE = KE + PE
Description of an object in projectile motion is;
- Gravity acts to pull the object down.
- The object’s inertia carries it forward.
- The path of the object is curved.
Explanation:
The path of the projectile is usually curved, and NOT straight, due to the influence of gravity on it which is teh only force acting on it-, causing it motion path to fall towards the earth. Most projectiles follow a parabolic path. The projectile, even though it was launched, its motion is then only due to its own inertia – tendency to stay in motion in a straight line, or rest, unless an external force is acting on it - such as drag or friction. An example of such projectile motion is of ballistic missiles.
3-m-high large tank is initially filled with water. The tank water surface is open to the atmosphere, and a sharp-edged 10-cm-diameter orifice at the bottom drains to the atmosphere through a horizontal 80-m-long pipe. If the total irreversible head loss of the system is determined to be 1.5 m, determine the initial velocity of the water from the tank. Disregard the effect of the kinetic energy correction factors.
