-3 im am sure its correct
If you would like to know what is the solution to the system of equations, you can calculate this using the following steps:<span>
2d + e = 8
d - e - 4 = 0 ... d = e + 4
___________________
</span>
<span>2d + e = 8
</span><span>2 * (e + 4) + e = 8
2e + 8 + e = 8
3e = 0
e = 0
d = e + 4 = 0 + 4 = 4
(d, e) = (4, 0)
The correct result would be: C. The solution is (4, 0).</span>
Answer:
The chosen topic is not meant for use with this type of problem. Try the examples below.
x
+
6
y
=
5
6
x
+
2
y
=
8
x
−
y
+
4
=
8
Use the given functions to set up and simplify
2
.
x
y
=
−
1
=
3
=
−
1
=
2
=
0
−
4
=
−
4
4
=
−
4
2
=
−
4
Step-by-step explanation:
Find the equation with a point and y-intercept.
y
=
(
y/
x − y
) x + x
y
The chosen topic is not meant for use with this type of problem. Try the examples below.
(
0
,
9
) , (
8
,
6
)
(
0
,
9
) , (
5
,
4
) , (
1
,
4
)
(
1
,
2
) , (
3
,
4
)
Step-by-step explanation:
for part a
initial means starting point and starting point is always 0
so the question means number of thousands of bacteria in 0 hours, your n being the number of hours. so in part a u will simply just put 0 as n in equation
2^(0+3)
2³=8 thousands of bacteria
in part b
2^(n+3) means total number of bacteria
2^(n-1) is number of groups
its asking for number of bacteria in each group
so u will simply divide number of bacteria by groups
its like u have 30 candies and there are 5 groups and they ask u to find number of candies in each group so u simply divide 30 by 5
so 2^(n+3)/2^(n-1)
base is same so powers will subtract since there is division sign
2^(n+3-(n-1))
2^(n+3-n+1)
2^(3+1)
2^4= 16 thousands of bacteria in each group