The question is incomplete. The complete question is :
Victor is selling lemonade to raise money for his school. The amount of money he collected from his sales each day is summarized on the box plot below.
What is the interquartile range of the data ?
Answer:
$ 7
Step-by-step explanation:
It is given that Victor sold lemonade in order to raise money for his school.
The money that Victor collected is shown on the diagram below.
Therefore, we find the interquartile range. It is the difference between the 3rd quartile and the 1st quartile, i.e.
IQR = 
Now from the figure, the 3rd quartile is the value that is at the end of the rectangular box towards the right. Therefore, the 3rd quartile is = $ 29
Similarly from the figure the 1st quartile at the beginning of the rectangular box to the left is = $ 22
So the interquartile range is = 3rd quartile - 1st quartile
= 29 - 22
= $ 7
Thus the amount of money Victor collected is $ 7.
Answer:
The answers should be
x^2 + 8x + 7
x(x + 8) +7
Step-by-step explanation:
(x + 7)(x + 1)
x(x) + x(1) + 7(x) + 7(1)
x^2 + x + 7x + 7
x^2 + 8x + 7
Answer:
3.8ft
Step-by-step explanation:
Given data
The total length of the rope= 9ft
We are told that 4ft was cut
=9-4
=5ft
Also, 14 inches from the rope was cut
=14 in to ft
=1.16667ft
=5-1.16667
=3.8ft
Hence the remainder is 3.8ft
<span>The first quartile (Q1) is defined as the middle number between the smallest number and the median of the data set.</span>