Answer:
pH = 3.215
Explanation:
From the given information;
Using the equation for the dilution of a stock solution:
Since moles of C5H5N = moles of HNO3
Then:
The reaction between C5H5NH and H2O is as follows:
⇄ 
Now, the next step is to draw out the I.C.E table.
⇄
I 0.06333 0 0
C - x x x
E 0.06333 -x x x
![K_a = \dfrac{[C_5H_5N][H_3O^+] }{[C_5H_5N^+H] } \\ \\ 5.8824 \times 10^{-6} = \dfrac{x^2}{0.06333 - x}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5BC_5H_5N%5D%5BH_3O%5E%2B%5D%20%7D%7B%5BC_5H_5N%5E%2BH%5D%20%7D%20%20%5C%5C%20%5C%5C%20%205.8824%20%5Ctimes%2010%5E%7B-6%7D%20%3D%20%5Cdfrac%7Bx%5E2%7D%7B0.06333%20-%20x%7D)
Assuming x < 0.06333
Then
![[H_3O^+] = x = 6.1035 \times 10^{-4} \ M \\ \\ pH = -log (6.1035 \times 10^{-4}) \\ \\ \mathbf{\\ pH = 3.215}](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%20%3D%20%20x%20%3D%206.1035%20%5Ctimes%2010%5E%7B-4%7D%20%5C%20M%20%20%5C%5C%20%5C%5C%20%20pH%20%3D%20-log%20%286.1035%20%5Ctimes%2010%5E%7B-4%7D%29%20%5C%5C%20%5C%5C%20%5Cmathbf%7B%5C%5C%20pH%20%3D%203.215%7D)
The patient can be subjected to intraoperative cholangiography wherein a stent in the bile duct will be placed and a radiopaque dye will be injected. X-rays will be taken. This is to locate the level of obstruction and to confirm if there is a common bile duct obstruction. In extracting stones, the surgeon can prefer doing an endoscopic retrograde cholangiopancreatography or ERCP and perform basket extraction of the common bile duct stone; or to surgically remove the sphincter of Oddi to allow easy passage of the stones.
Answer:
for 7
Explanation:
7.If the leptons of mosses were found to contain a protein whose gene had the same nucleotide sequence as the gene that codes for P-protein, would that be significant evidence for either the homo-logy or analogy of leptons and phloem?
