Humans affect the levels of air pollution by using natural resources and

An unknown solution has a pH of 8

Anarel [89]

<h2>Answer:</h2>

Solution is unknown but its PH is indicating that it is a <u>slight Basic solution</u>.

So solution can be sea water or eggs.

6 0

3 years ago

If you have a gas that starts out with a pressure of 720 mm Hg and a volume of 1500mL, what is the new volume if you increase th

Bad White [126]

the new volume is calculated by use of Boyles law formula

that is P1V1=p2v2

v2= p1v1/p2

P1= 720 mmhg
v1= 1500ml
p2 = 2 atm
V2=?
convert P2 to mmhg = 2 x760= 1520 mmhg

V2= 720mmhg x1500 ml/ 1520mmhg = 710.53 ml

3 0

3 years ago

1. The gases SO2, O2 and SO3 are allowed to reach equilibrium at a constant temperature. The equilibrium constant for the reacti

irina [24]

Answer:

a)

$K_2=1.3x10^{2}atm^{-1/2}$

b)

$PCl_5\rightarrow PCl_3+Cl_2$

$[PCl_5]=0.0375M$

Explanation:

Hello!

a) In this case, since we can see that the second reaction is equal to the half of the first reaction, we can relate the equilibrium constants as shown below:

$K_2=K_1^{1/2}$

Thus, by plugging in the the equilibrium constant of the first reaction we obtain:

$K_2=(1.6x10^4atm^{-1})^{1/2}\\\\K_2=1.3x10^{2}atm^{-1/2}$

b) In this case, for the described reaction we can write:

$PCl_5\rightarrow PCl_3+Cl_2$

Thus, the corresponding equilibrium expression is:

$K=\frac{[PCl_3][Cl_2]}{[PCl_5]}$

In such a way, since we know the equilibrium constant and the concentrations of PCl3 and Cl2 at equilibrium, we can compute the concentration of PCl5 at equilibrium as follows:

$[PCl_5]=\frac{[PCl_3][Cl_2]}{K}\\$

$[PCl_5]=\frac{\frac{0.20mol}{4L} *\frac{0.12mol}{4L} }{0.04}$

$[PCl_5]=0.0375M$

Best regards!

7 0

2 years ago

For the following reaction if you have 13.2g of CO and 42.7g of Fe2O3, which is the limiting reagent with regards to the Fe prod

MrRissso [65]

Answer: CO is a limiting reagent with regards to the Fe production.

Explanation:

$Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(s)+3CO_2(g)$

Moles of CO = $\frac{\text{mass of CO}}{\text{molar mass of CO}}=\frac{13.2 g}{28 g/mol}=0.4714 mol$

moles of $Fe_2O_3=\frac{\text{mass of} Fe_2O_3}{\text{molar mass of}Fe_2O_3}=\frac{42.7 g g}{159.7 g/mol}=0.2673 mol$

According to reaction , 3 mole of CO reacts with 1 mole of $Fe_2O_3$ then , 0.4714 moles of CO will react with : $\frac{1}{3}\times 0.4714$ moles of $Fe_2O_3$ that is 0.1571 moles.

0.4714 moles of CO will react with 0.1571 moles of $Fe_2O_3$ which means that CO is present in limited amount acting as limiting reagent.

Mole remaining of $Fe_2O_3$ = 0.2673 mol - 0.1571 mol = 0.1102 mol

Hence, CO is a limiting reagent and $Fe_2O_3$ is an excessive reagent.

8 0

3 years ago

How is an amp defined?

faust18 [17]

Answer:

The amplitude of a periodic variable is a measure of its change over a single period. There are various definitions of amplitude, which are all functions of the magnitude of the difference between the variable's extreme values. In older texts the phase is sometimes called the amplitude

if you mean amplitude

Explanation:

4 0

2 years ago