Answer:
5.625 moles of oxygen, O₂.
Explanation:
The balanced equation for the reaction is given below:
4Al + 3O₂ —> 2Al₂O₃
From the balanced equation above,
4 moles of Al reacted with 3 moles of O₂.
Finally, we shall determine the number of mole of O₂ required to react with 7.5 moles of aluminum, Al. This can be obtained as illustrated below:
From the balanced equation above,
4 moles of Al reacted with 3 moles of O₂.
Therefore, 7.5 moles of Al will react with = (7.5 × 3)/4 = 5.625 moles of O₂.
Thus, 5.625 moles of O₂ is needed for the reaction.
Answer:
The final volume should be 22 mL
Explanation:
For this problem, we will use the dilution equation:
C1*V1 = C2*V2
<u>Step 1</u>: Data given
with C1 = the initial concentration C1 = 0.220 mg/L
with V1 = the initial volume = 10 mL = 10 * 10^-3 L
with C2 = the final concentration = 0.100 mg/L
with V2 = the final volume = TO BE DETERMINED
<u>Step 2</u>: Calculating the final volume
C1*V1 = C2*V2
0.220 mg/L * 10*10^-3 L = 0.100 mg/L * V2
V2 = (0.220 mg/L * 10*10^-3 L) / 0.100 mg/L
V2 =0.022 L = 22 mL
The final volume should be 22 mL
An experimental group, also known as a treatment group, receives the treatment whose effect researchers wish to study, whereas a control group does not. They should be identical in all other ways
Answer:
The metalloids are a unique group of elements that share properties of both metals and nonmetals. They're also called the semimetals because of the shared properties of these elements along the dividing line between metals and nonmetals.
Elements: Arsenic
