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Alex
3 years ago
6

If in the following diagram the substance is in solid form during stage 1, what is happening during stage 3?

Chemistry
2 answers:
yulyashka [42]3 years ago
6 0

Answer : The stage 3 shows the liquid state of a substance.

Explanation :

In the given phase diagram,

Stage 1 : It shows the solid state of a substance.

Stage 2 : It shows the melting and freezing process of a substance. It means that when the phase changes from solid state to liquid state at constant temperature is know as melting process and when the phase changes from liquid state to solid state at constant temperature is know as freezing process.

Stage 3 : It shows the liquid state of a substance.

Stage 4 : It shows the evaporation and condensation process of a substance. It means that when the phase changes from liquid state to gaseous state at constant temperature is know as evaporation process and when the phase changes from gaseous state to liquid state at constant temperature is know as condensation process.

Stage 5 : It shows the gaseous state of a substance.

Hence, from the above information we conclude that the stage 3 shows the liquid state of a substance.

Rufina [12.5K]3 years ago
5 0
Its converting from a solid to a liquid.
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The kilocalories in one can of cola if it has 40. g of carbohydrate and no fat or<br> protein
Marysya12 [62]

Answer:

One can of cola contain 0.16 kcal of carbohydrates.

Explanation:

Given data:

mass of cola can = 40 g

kilocalories of carbohydrates = ?

Solution:

we know that there are 4 cal of carbohydrates per gram.

40 g × 4 cal/g = 160 cal

Now we will convert calories into kilocalories. There are 1000 calories in one kilocalories so,

160/1000 = 0.16 kcal

so, one can of cola contain 0.16 kcal of carbohydrates.

6 0
3 years ago
Write the chemical equations involved in this experiment and how that the rate of disappearance of [S2O8^2-] is proportional to
Ne4ueva [31]

S₂O₈²⁻

(aq) + 2I⁻

(aq) → I₂(aq) + 2SO₄

²⁻(aq)

2S₂O₃²⁻

(aq) + I₂(aq) → S₄O₆²⁻

(aq) + 2I⁻

(aq)

<u>Explanation:</u>

S₂O₈²⁻

(aq) + 2I⁻

(aq) → I₂(aq) + 2SO₄

²⁻(aq)

To measure the rate of this reaction we must measure the rate of concentration change of one of  the reactants or products. To do this, we will include (to the reacting S₂O₈

²⁻  and I⁻

i) a small amount of sodium thiosulfate, Na₂S₂O₃,

ii) some starch indicator.

The added Na₂S₂O₃ does not interfere with the rate of above reaction, but it does consume the I₂  as soon as it is formed.

2S₂O₃²⁻

(aq) + I₂(aq) → S₄O₆²⁻

(aq) + 2I⁻

(aq)

This reaction is much faster than the previous, so the conversion of I2 back to I⁻  is  essentially instantaneous.

rate = \frac{dI2}{dt} = \frac{1/2 [S2O3^2^-]}{t}

5 0
3 years ago
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BabaBlast [244]

Answer: check explanation

Explanation:

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7 0
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Answer:

Explanation:

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5 0
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