Which of these does not describe a form of electomagnetic radiation?

Earth is one of the planets in the

prisoha [69]

Answer:

moon obviously

Explanation:

........

6 0

2 years ago

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Which option is an example of a physical property?

Setler79 [48]

Freezing point. because toxicity is a chemical property as well as pH and flammability is dependent on the items chemical composition <span />

5 0

3 years ago

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Explain why the following are made of thermosetting plastics.

rusak2 [61]

Answer:

a: they're used in saucepan handles 'cause they don't soften when heated and also 'cause they cant be bent easily.

b: thermosetting plastics are bad electricity conductors. they don't get moulded and are also hard and strong.

6 0

3 years ago

16. Which of the following aqueous solutions contains the greatest number of 10ns.

gavmur [86]

Answer:

$\boxed{\text{b) 300.0 mL of 0.10 mol/L CaCl}_{2}}$

Explanation:

a) 400.0 mL of 0.10 M NaCl

(i) Moles of NaCl

$\text{ Moles of NaCl } = \text{0.4000 L NaCl} \times \dfrac{\text{0.10 mol NaCl}}{\text{1 L NaCl}} = \text{0.040 mol NaCl}$

(ii) Moles of ions

NaCl(s) ⟶ Na⁺(aq) + Cl⁻(aq)

We get 2 mol of ions from 1 mol of NaCl

$\text{Moles of ions } = \text{0.040 mol NaCl} \times \dfrac{\text{2 mol ions}}{\text{1 mol NaCl}} = \text{0.080 mol ions}$

b) 300.0 mL of 0.10 M CaCl₂

(i) Moles of CaCl₂

$\text{ Moles of CaCl}_{2} =\text{0.3000 L CaCl}_{2} \times \dfrac{\text{0.10 mol CaCl}_{2}}{\text{1 L CaCl}_{2}} = \text{0.030 mol CaCl}_{2}$

(ii) Moles of ions

CaCl₂(s) ⟶ Ca²⁺(aq) + 2Cl⁻(aq)

We get 3 mol of ions from 1 mol of CaCl₂

$\text{Moles of ions } = \text{0.030 mol CaCl}_{2} \times \dfrac{\text{3 mol ions}}{\text{1 mol CaCl}_{2}} = \text{0.090 mol ions}$

c) 200.0 mL of 0.10 M FeCl₃

(i) Moles of FeCl₃

$\text{ Moles of FeCl}_{3} =\text{0.2000 L FeCl}_{3} \times \dfrac{\text{0.10 mol FeCl}_{3}}{\text{1 L FeCl}_{3}} = \text{0.020 mol FeCl}_{3}$

(ii) Moles of ions

FeCl₂(s) ⟶Fe³⁺(aq) + 3Cl⁻(aq)

We get 4 mol of ions from 1 mol of FeCl₃

$\text{ Moles of FeCl}_{3} =\text{0.2000 L FeCl}_{3} \times \dfrac{\text{0.10 mol FeCl}_{3}}{\text{1 L FeCl}_{3}} = \text{0.020 mol FeCl}_{3}$

d) 200.0 mL of 0.10 M KBr

(i) Moles of KBr

$\text{ Moles of KBr} = \text{0.2000 L KBr} \times \dfrac{\text{0.10 mol KBr }}{\text{1 L KBr}} = \text{0.020 mol KBr}$

(ii) Moles of ions

KBr(s) ⟶ K⁺(aq) + Br⁻

We get 2 mol of ions from 1 mol of KBr

$\text{Moles of ions } = \text{0.020 mol KBr} \times \dfrac{\text{2 mol ions}}{\text{1 mol KBr}} = \text{0.040 mol ions}\\\\\text{We get the most ions ions from }\boxed{\textbf{300.0 mL of 0.10 mol/L CaCl}_{2}}$

8 0

2 years ago

Please help me ASAP PLEASE

vodomira [7]

24 cm^3 CO2 / 1 * 1 dcm^3 / 1000 cm^3 * 1 mol / 24 dcm^3 = 0.001 mol of CO3 is required

3 0

2 years ago