Answer : The equilibrium concentration of
is, 0.50 M
Explanation : Given,
Initial moles of
= 0.65 mole
Volume of solution = 1.0 L
Moles of
at equilibrium = 0.15 mole
The balanced equilibrium reaction will be,

Initial moles 0.65 0 0
At eqm. (0.65-x) x x
Moles of
at equilibrium = x = 0.15 mole
Moles of
at equilibrium = x = 0.15 mole
Moles of
at equilibrium = (0.65-x) = (0.65-0.15) = 0.50 mole
Now we have to calculate the concentration of
at equilibrium.
Formula used : 



Therefore, the equilibrium concentration of
is, 0.50 M
Answer:
6.82 moles of Fe2O3
Explanation:
Step 1:
Determination of the number of mole of in 450g of CO2.
This is illustrated below:
Molar Mass of CO2 = 12 + (2x16) = 44g/mol
Mass of CO2 = 450g
Number of mole of CO2 =.?
Number of mole = Mass/Molar Mass
Number of mole of CO2 = 450/44 = 10.23 moles
Step 2:
Determination of the number of mole of Fe2O3 needed for the reaction. This is illustrated below:
2Fe2O3 + 3C—> 4Fe + 3CO2
From the balanced equation above,
2 moles of Fe2O3 reacted to produce 3 moles of CO2.
Therefore, Xmol of Fe2O3 will react to produce 10.23 moles of CO2 i.e
Xmol of Fe2O3 = (2x10.23)/3
Xmol of Fe2O3 = 6.82 moles
Therefore, 6.82 moles of Fe2O3 is required.
Mitosis has one round of cellular division and genetic separation whereas meiosis has two rounds. The two processes are also different because in mitosis the daughter cells are exactly identical to the parent cells compared to meiosis where the daughter cells are not genetically identical to the parent cells
Hope this helped
how many protons it has/atomic number and atomic mass if that what ur trying to ask