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eduard
3 years ago
8

Which of the following determines the type of tree species found in a temperate broadleaf forest? (Select all that apply.)

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

Answer: A B C

Explanation: chapter 34-45 pdf

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oth hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you opene
Ksju [112]

Answer: Odor of ammonia would we detect first on the other side of the room.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{M_{NH_3}}{M_{H_2S}}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=\sqrt{\frac{17.031}{34.1}}

\frac{Rate_{H_2S}}{Rate_{NH_3}}=0.71

Thus the odor of ammonia would we detect first on the other side of the room as the rate of effusion of ammonia would be faster as it has low molecular weight as compared to hydrogen sulphide.

5 0
3 years ago
Read 2 more answers
Which best describes an element? A pure substance. A type of a mixture. A pure compound. An impure substance.
mr Goodwill [35]

a pure compound because an element is untouched and is just itself

7 0
3 years ago
Read 2 more answers
What is the entropy change for the freezing process of 1 mole of liquid methanol at its freezing temperature (–97.6˚C) and 1 atm
Rudiy27

Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K

Explanation :

Formula used :

\Delta S=\frac{\Delta H_{freezing}}{T_f}

where,

\Delta S = change in entropy

\Delta H_{fus} = change in enthalpy of fusion = 3.17 kJ/mol

As we know that:

\Delta H_{fus}=-\Delta H_{freezing}=-3.17kJ/mol=-3170J/mol

T_f = freezing point temperature = -97.6^oC=273+(-97.6)=175.4K

Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{freezing}}{T_m}

\Delta S=\frac{-3170J/mol}{175.4K}

\Delta S=-18.07J/mol.K

Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K

4 0
4 years ago
These goats are eating grass on a sunny day. What is happening to the carbon in the air around the living things on the mountain
polet [3.4K]

Answer:

both

Explanation:

Carbon in the air around the living thing is moving in and out of its lungs. The movement is occurring at the same time. This is one of the most important gaseous exchange important to life.

  • The goats takes in oxygen gas from the surrounding and releases carbon dioxide in the process.
  • But, air is actually drawn in by the goat which is a mixture of several gases.
  • Air contains carbon dioxide which is a rich source of carbon
  • With the carbon dioxide from respiratory processes, the goat ejects and breathes out this waste carbon matter.
  • Therefore, the gaseous exchange in a goat involves the movement of carbon in and out of the air.
8 0
4 years ago
Breve resumen de que es volumen
andrey2020 [161]
What??? what language is this?
4 0
3 years ago
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