C. Also just look up a chemical equation balancer calculator next time.
The reaction formula CH4 + 2O2 → CO2 + 2H2O shows the oxidation of 1 mole of CH4 (Methane) will yield 1 mole of CO2 (Carbon Dioxide). Since 1 mole of CH4 will weigh 12g (for the Carbon) + 4g (1g for each Hydrogen) = 16g, then 32g of CH4 will correspond to 32g / 16g/mole = 2 moles. Therefore the oxidation of 2 moles of CH4 will yield 2 moles of CO2.
One example of matter could be <em>Light.</em>
5.2e+26is it this? im not sure
Answer:
Limiting reactant = B2O3
Amount of BCl3 formed = 468 g
Explanation:
The given reaction is:

In order to identify the limiting reagent calculate the moles of B2O3, C and Cl2. The reagent with the lowest moles is the limiting reactant



Since the moles of B2O3 < C < Cl2, the limiting reactant is B2O3
Based on the reaction stoichiometry:
1 mole of B2O3 produces 2 moles of BCl3
Hence, the number of moles of BCl3 produced under the experimental conditions = 2*1.997=3.994 moles
