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Montano1993 [528]
3 years ago
9

Which represents potential energy? A)bread baking B)lawnmower cutting grass C)car racing downhill D)weed whacker full of gas

Chemistry
2 answers:
malfutka [58]3 years ago
6 0
I think it might be A because the bread is baking so the heat energy is stored inside of the bread while it’s baking and rising in size
Marizza181 [45]3 years ago
5 0
Potential energy is the energy stored. What do u think it is? (I don't really know)
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ANSWER ASAP! PLEASE!!!!!
Rina8888 [55]
C. Also just look up a chemical equation balancer calculator next time.
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2 years ago
How many moles of methane are produced when 4.53 mol co2 reacts
ArbitrLikvidat [17]
The reaction formula CH4 + 2O2 → CO2 + 2H2O shows the oxidation of 1 mole of CH4 (Methane) will yield 1 mole of CO2 (Carbon Dioxide). Since 1 mole of CH4 will weigh 12g (for the Carbon) + 4g (1g for each Hydrogen) = 16g, then 32g of CH4 will correspond to 32g / 16g/mole = 2 moles. Therefore the oxidation of 2 moles of CH4 will yield 2 moles of CO2.
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2 years ago
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One example of matter is​
zaharov [31]

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3 years ago
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5.2*10^26 molecules of ch4 in volume
aivan3 [116]
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4 0
3 years ago
Consider the reaction of diboron trioxide with carbon and chlorine. B2O3 (s) + 3C (s) + 3Cl2 (g) 2BCl3 (g) + 3CO (g) Determine t
Sholpan [36]

Answer:

Limiting reactant = B2O3

Amount of BCl3 formed = 468 g

Explanation:

The given reaction is:

B2O3 (s) + 3C (s) + 3Cl2 (g) \rightarrow 2BCl3 (g) + 3CO (g)

In order to identify the limiting reagent calculate the moles of B2O3, C and Cl2. The reagent with the lowest moles is the limiting reactant

Moles(B2O3)=\frac{Mass(B2O3)}{Mol.wt(B2O3)}=\frac{139g}{69.6g/mol}=1.997moles

Moles(C)=\frac{Mass(C)}{At.wt(C)}=\frac{87.8g}{12g/mol}=7.317moles

Moles(Cl2)=\frac{Mass(Cl2)}{Mol.wt(Cl2)}=\frac{650g}{70.9g/mol}=9.168moles

Since the moles of B2O3 < C < Cl2, the limiting reactant is B2O3

Based on the reaction stoichiometry:

1 mole of B2O3 produces 2 moles of BCl3

Hence, the number of moles of BCl3 produced under the experimental conditions = 2*1.997=3.994 moles

Mass(BCl3)= Moles* Mol.wt = 3.994 moles*117.17g/mol = 468 g

8 0
3 years ago
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