Answer:
49.95 g of HCl
Explanation:
Let's formulate the chemical equation involved in the process:
Ca(OH)2 + 2 HCl → CaCl2 + 2 H2O
This means that we need 1 mole of Calcium hydroxide to neutralize 2 moles of hydrochloric acid. From this, we calculate the quantity of HCl moles that would be neutralized by 0.685 moles of Ca(OH)2
1 mole Ca(OH)2 ---- 2 moles HCl
0.685 moles Ca(OH)2 ---- x = 1.37 moles HCl
Now that we know the quantity of HCl moles that would react, let's calculate the quantity of grams this moles represent:
1 mole of HCl ---- 36.46094 g
1.37 moles ------ x = 49.95 g of HCl
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450.0 ML because it has more solution and it would be better if the sciences users it
On the basis of the given data:
Volume (V) is 37.5 L
Temperature (T) is 307 K
Pressure (P) is 1.25 atm
In order to calculate the number of moles, the formula to be used is PV = nRT, Here R is 0.0821 Latm/mol/K
n = PV / RT
n = 1.25 atm × 37.5 L / 0.0821 Latm/mol/K × 307 K
n = 1.85 mol
