All categories

3 years ago

Help? please and thank you! very much appreciated

Chemistry

1 answer:

Triss [41]3 years ago

4 0

Answer:

Option B is correct

Explanation:

The Formula of Nitrate is NO₃⁻

-TheUnknownScientist

You might be interested in

What action will result in a product with new chemical properties

jeka94

Your answer is popping popcorn

hopes this helps

5 0

3 years ago

Read 2 more answers

What happens to the air in the colloid when ice cream melts

Contact [7]

The colloid formed by ice cream remains stable only at cold temperatures. When ice cream is warmed above freezing, its dispersed particles absorb energy and begin to move faster. When the fast-moving particles collide, they sometimes stick together.

7 0

3 years ago

The standard free-energy changes for the reactions below are given.Phosphocreatine → creatine + Pi ∆ G'° = –43.0 kJ/molATP → ADP

Anton [14]

Answer:

Gibbs free-energy of the reaction = (–12.5 kJ/mol)

Explanation:

The Gibbs free-energy of a reaction predicts the spontaneity or feasibility of a given chemical reaction.

Given the standard Gibbs free energy changes:

Phosphocreatine → creatine + Pi, ∆G° = –43.0 kJ/mol ...(1)

ATP → ADP + Pi , ∆G° = –30.5 kJ/mol ....(2)

Now to calculate the Gibbs free-energy of the given chemical reaction: Phosphocreatine + ADP → creatine + ATP; the equation (2) is reversed to give:

ADP + Pi → ATP, ∆G° = + 30.5 kJ/mol ...(3)

Now the equation (3) and (1) are added, to give:

Phosphocreatine + ADP + Pi→ creatine + ATP + Pi

⇒ Phosphocreatine + ADP → creatine + ATP

Therefore, to calculate the Gibbs free-energy of the reaction, the standard Gibbs free energy changes of the equations (1) and (3) are added similarly:

Gibbs free-energy of the reaction: ∆G° = (–43.0 kJ/mol) + ( + 30.5 kJ/mol) = (–12.5 kJ/mol)

Therefore, the Gibbs free-energy of the reaction = (–12.5 kJ/mol)

7 0

3 years ago

The value of Kc for the reaction between water vapor and dichlorine monoxide, H2O(g) 1 Cl2O(g) 4 2 HOCl(g) is 0.0900 at 25°C. De

max2010maxim [7]

Answer:

[HOCl] = 0.001 127 mol·L⁻¹; [H₂O] = [Cl₂O] = 0.003 76 mol·L⁻¹

Explanation:

The balanced equation is

H₂O + Cl₂O ⇌ 2HOCl

Data:

Kc = 0.0900

[H₂O] = 0.004 32 mol·L⁻¹

[Cl₂O] = 0.004 32 mol

1. Set up an ICE table.

$\begin{array}{ccccccc}\rm \text{H$_{2}$O}& + & \text{Cl$_{2}$O} & \, \rightleftharpoons \, & \text{2HOCl} & & \\0.00432 & & 0.00432 & & 0 & & \\-x &&-x&&+2x&&\\0.00432-x &&0.00432 - x& & 2x&&\\\end{array}$

2. Calculate the equilibrium concentrations

$K_{\text{c}} = \dfrac{\text{[HOCl]$^{2}$}}{\text{[H$_{2}$O][Cl$_2$O]}} = \dfrac{(2x)^{2}}{(0.00432 - x)^{2}} = 0.0900\\\\\begin{array}{rcl}\dfrac{4x^{2}}{(0.00432 - x)^{2}} &=& 0.0900\\ \dfrac{2x }{0.00432 - x} & = & 0.300\\2x & = & 0.300(0.00432 - x)\\2x & = & 0.001296 - 0.300x\\2.300x & = & 0.001296\\x & = & \mathbf{5.63\times 10^{-4}}\\\end{array}$

[HOCl] = 2x mol·L⁻¹ = 2 × 5.63 × 10⁻⁴ mol·L⁻¹ =0.001 127 mol·L⁻¹

[H₂O] = [Cl₂O] = (0.004 32 - 0.000 563) mol·L⁻¹ = 0.003 76 mol·L⁻¹

Check:

$\begin{array}{rcl}\dfrac{0.001127^{2}}{0.00376^{2}} & = & 0.0900\\\\\dfrac{1.270 \times 10^{-6}}{1.411 \times 10^{-5}} & = & 0.0900\\0.0900 & = & 0.0900\\\end{array}$

OK.

7 0

3 years ago

The difference between ATP and the nucleoside triphosphates used during DNA synthesis is that:

12345 [234]

Answer:

The correct answer is d. The nucleoside triphosphates have the sugar deoxyribose; ATP has the sugar ribose.

Explanation:

The nucleoside triphosphates are components of DNA (deoxyribonucleic acid) so they are composed by a nitrogenous base (adenine, guanine, thymine or cytosine) and a deoxyribose sugar. In contraposition, ATP (adenosine triphosphate) is composed by the nitrogenous base adenine and a ribose sugar along with three phosphates groups. Unlike ribose, deoxyribose is a 5-carbon sugar which lack of an oxygen atom in C2 position.

4 0

3 years ago