Problem PageQuestion In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide dissol
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Complete Question
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Answer:
The sequence of these amino acid would be
<u>Lue</u> <u>Arg</u> <u>Lys</u> <u>Arg</u> <u>Met</u> <u>Phe</u> <u>Arg</u> <u>Ser</u>
Explanation:
The acid-catalyzed hydrolysis from makes us to understand that the polypeptides contains 8 amino acids
From the question we are told that the Edman's reagent releases Leu it means that the N-terminal amino acid would be Lue(i.e Leucine)
Also from the question we are told that the Carboxypeptidase released Ser this mean the the C-terminal amino acid would be Ser ( i.e Serine)
The Amino acids would in the polypeptides would be arranged like this
<u>Lue</u> __ __ __ __ __ __ <u>Ser</u>
Now from the question we are told that treatment with cranogen bromide form two peptides.
Now generally cranogen bromide divides a peptide on the C- side(i.e the extreme left side ) of Met(Methionine)(This is an amino acid obtained by hydrolysis of most common peptides )
So this means that any peptides containing Met(Methionine) must have Methionine as a C- terminal amino acid(i.e at extreme left) and for peptides that does not contain Met must be C - terminal peptides
From the question we see that it is the second peptide that contain Met and it is a penta peptide(i.e it contains 5 amino acid)
Thus the fifth amino acid is Met
So the sequence of these amino acid would now be
<u>Lue</u> __ __ __ <u>Met</u> __ __ <u>Ser</u>
From the question we are told that the the Trypsin-catalyzed hydrolysis forms two amino acid and two peptides
Now generally Trypsin divides a peptide on the C- side(i.e the extreme left) of Arg(Arginine) and Lys (lysine) and any peptide that holds Arg or Lys must have them as their C- terminal amino acids
From the first peptide in the two peptide formed we see that Arg would be the Seventh amino acid of the octapeptide because commonly the trypsin that sticks to the C-side of Arg would for Ser
and Phe would be the sixth amino acid of the octapeptide
So the sequence of these amino acid would be
<u>Lue</u> __ __ __ <u>Met</u> <u>Phe</u> <u>Arg</u> <u>Ser</u>
Looking at the first amino acid formed from the Trypsin-catalyzed hydrolysis we see that Arg would be the fourth amino acid of octapeptide as Trypsin divides a peptide on the C- side(i.e the extreme left) of Arg(Arginine).
From the second peptide of the Trypsin-catalyzed hydrolysis we see that Lys would be the third amino acid of the octapeptide as trypsin divides on the C- side of Lys (lysine) and Tyr would be the second amino acid of the octapeptide
So the sequence of these amino acid would be
<u>Lue</u> <u>Arg</u> <u>Lys</u> <u>Arg</u> <u>Met</u> <u>Phe</u> <u>Arg</u> <u>Ser</u>
