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3 years ago

A reaction produced 37.5 L of oxygen gas at 307 K and 1.25 atm. How many moles of oxygen were produced?

Chemistry

1 answer:

MariettaO [177]3 years ago

3 0

On the basis of the given data:

Volume (V) is 37.5 L

Temperature (T) is 307 K

Pressure (P) is 1.25 atm

In order to calculate the number of moles, the formula to be used is PV = nRT, Here R is 0.0821 Latm/mol/K

n = PV / RT

n = 1.25 atm × 37.5 L / 0.0821 Latm/mol/K × 307 K

n = 1.85 mol

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

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Exponents
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Division
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Left to Right

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