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Eva8 [605]
3 years ago
7

What is volcanoes be my friend

Chemistry
2 answers:
andreev551 [17]3 years ago
5 0
Volcanos are mountains with lava inside I’ll be you friend
Bess [88]3 years ago
4 0
....wut?.......is that a book or something??
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(vii). Give two uses of chlorine gas.​
Strike441 [17]

Answer: A yellowy-green dense gas with a choking smell. Chlorine kills bacteria – it is a disinfectant. It is used to treat drinking water and swimming pool water. It is also used to make hundreds of consumer products from paper to paints, and from textiles to insecticides.

Explanation: hope this helps u! HAppy Holidays!  

7 0
3 years ago
4.7C Renewable and Nonrenewable Resources
ki77a [65]
Answer: petroleum
because it is a fossil fuel like coal, and natural gas.
4 0
3 years ago
Why hyberdization occurs?
Damm [24]
Because the resulting hybridized orbitals are more stable
8 0
3 years ago
If exactly 59.6 g of nitrogen gas is needed to inflate your air bag to the
Inga [223]

Answer:

We need 92.3 grams of sodium azide

Explanation:

Step 1: Data given

Mass of nitrogen gas = 59.6 grams

Molar mass of nitrogen gas = 28.0 g/mol

Molar mass of sodium azide = 65.0 g/mol

Step 2: The balanced equation

2NaN3 → 2Na + 3N2

Step 3: Calculate moles nitrogen gas

Moles N2 = mass N2 / molar mass N2

Moles N2 = 59.6 grams/ 28.0 g/mol

Moles N2 = 2.13 moles

Step 4: Calculate moles NaN3

for 2 moles NaN3 we'll have 2 moles Na and 3  moles N2

For 2.13 moles N2 we need 2/3* 2.13 = 1.42 moles NaN3

Step 5: Calculate mass NaN3

Mass NaN3 = Moles NaN3 * molar mass NaN3

Mass NaN3 = 1.42 moles * 65.0 g/mol

Mass NaN3 = 92.3 grams

We need 92.3 grams of sodium azide

7 0
3 years ago
If an automobile air bag has a volume of 11.7 L, what mass of NaN3 (in g) is required to fully inflate the air bag upon impact
Usimov [2.4K]

Answer:

33.95 grams of NaN3

Explanation:

Number of moles of NaN3 = mass (m)/MW = m/65 mole

I mole of NaN3 requires 22.4L air bag

m/65 mole of NaN3 required 11.7L

22.4m/65 = 11.7

22.4m = 65×11.7

22.4m = 760.5

m = 760.5/22.4 = 33.95grams of NaN3

5 0
3 years ago
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