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balandron [24]
3 years ago
13

What is the additive inverse of -3?

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer: 3

Step-by-step explanation: The additive inverse of -3 is 3.

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Hey can anyone help me with this problem please and thank you
krok68 [10]

Answer:

x=20

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The table shows the input and output of a function Table(input:3,4,6,11. Output:5,7,11,21) write an equation, in function nation
Anni [7]

f(x) = 2x - 1

To obtain a function we require values of x for x = 3, 4, 5 , 6, .....

The output appears to increase in steps of 2

3 → 5

4 → 7

5 → 9

6 → 11

Looking at the consecutive values of y we should see that these are twice the corresponding value of x subtract 1

f(x) = 2x - 1 ← is a possible function

checking the values for x in the input


f(3) =(2 × 3 ) - 1 = 5

f(4) = (2 × 4 ) - 1 = 7

f(6) = (2 × 6 ) - 1 = 11

f(11) = (2 × 11 ) - 1 = 21




6 0
3 years ago
Need help ASAP!! I'll give brainliest to whoever answers correctly!!!
jolli1 [7]

Answer:

SRT

Plzzzzz give me Brainliest!!!!!  

6 0
3 years ago
A fund earns a nominal rate of interest of 6\% compounded every two years. Calculate the amount that must be contributed now to
Nesterboy [21]

Answer:

$712.

Step-by-step explanation:

We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,  

n = Number of times interest is compounded per year,

t = Time in years.

6\%=\frac{6}{100}=0.06

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.

1000=P(1+\frac{0.06}{0.5})^{0.5*6}

1000=P(1+0.12)^{3}

1000=P(1.12)^{3}

1000=P*1.404928

\frac{1000}{1.404928}=\frac{P*1.404928}{1.404928}

P=711.7802478

P\approx 712

Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.

7 0
3 years ago
Can someone please help?
kipiarov [429]
The second one. Hope this helps:)

6,025, 305< 6,026,305< 6,027,305.
3 0
2 years ago
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