LiAlH₄ is used as strong reducing agent. The hydride produced acts as a nucleophile and attacks the electrophillic carbon of carbonyl group. In given example two reactions are observed.
Reaction 1: In first step LiAlH₄ when treated with
Ester produces corresponding
Aldehyde and alcohol.
Reaction 2: This aldehyde produced further reacts with LiAlH₄ to give a reduced product (
Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,
Map map map map map he keeps us on track when I leave home he go me back
<span>I think it is a but dont take me for it. I searched it and thats what I found since liquid in beaker B is more dense then realtivley speaking the object is less dense compared other liquid and floats at a higher level.</span>
Answer:
The phase transition from a solid to a gas.
Explanation:
Entropy is related to the moles of gases available. The more gaseous moles, the higher the entropy.
<em>Identify the process in which the entropy increases.</em>
- <em>the phase transition from a solid to a gas</em>. YES. There are more gaseous moles available so entropy increases.
- <em>a decrease in the number of moles of a gas during a chemical reaction</em>. NO. This causes a decrease in entropy.
- <em>the phase transition from a liquid to a solid</em>. NO. There is almost no change in the entropy in this process.
- <em>the phase transition from a gas to a liquid</em>. NO. There is a decrease in entropy in this process.
- <em>the phase transition from a gas to a solid</em>. NO. There is a decrease in entropy in this process.
Answer:
The temperature of the balloon is 46.34 K.
Explanation:
An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
In this case:
- P= 0.76 atm
- V= 10 L
- n= 2 moles
- R= 0.082
- T= ?
Replacing:
0.76 atm* 10 L= 2 moles* 0.082 *T
Solving:
T= 46.34 K
<u><em>The temperature of the balloon is 46.34 K.</em></u>
