Using the formula:
F = k.q1.q2/r2
Manipulating for r.
<span>r = √(Kq1q2/F)
r = </span><span>1.5 x 10^-2 meters</span>
The Patch's area of the space shuttle in km² is 2.07 × 10⁻⁹ km²
Given, that a space shuttle requires a 20.7 cm² patch
We have to convert the patch's area from cm² into km².
Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.
Patch area of the space shuttle is 20.7 cm²
1 cm = 0.00001 km
or, 1 cm² = (0.00001 km)²
or, 1 cm² = 10⁻¹⁰km²
20.7 cm² = 20.7 × 10⁻¹⁰km²
20.7 cm² = 2.07 × 10⁻⁹ km²
The patch area in square kilometers is 2.07 × 10⁻⁹ km²
To learn more about unit conversion, visit: brainly.com/question/11543684
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The independent variable would be the amount of sunlight because that is what you are testing and the dependent variable would be the length of time the mice slept because it is what you are measuring. The constants would be everything else water, food, cage size, exercise wheel, and temperature because they stay the same.
Answer:
D
Explanation:
7 is neutral on a PH scale. Anything less is an acid and anything higher is a base. A Ph scale goes from 1-13. 8.4-7=1.4. This is a small change so it is considered a weak base. Can I get brainliest?
