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Contact [7]
2 years ago
7

In kinetics, the order of a reaction

Chemistry
1 answer:
zalisa [80]2 years ago
4 0
I think it should be C.  You can't always look at the chemical equation of a reaction and tell what order the over all reaction will be.  To do this, you need to preform experiments that have some concentrations held constant while changing others to see how the concentrations affected the rate.  After enough trials with enough concentrations held constant and changed, you will be able to determine the order of each reactant which will give you the order of the overall reaction.

I hope this helps.  Let me know in the comments if anything is unclear.
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A colorless liquid has a molar mass of 60.01 g/mol. When the liquid was analyzed, it was 46.7% nitrogen and 53.3% oxygen. What i
MAXImum [283]

first we have to find the empirical formula of the compound

empirical formula is the simplest ratio of whole numbers of components making up a compound

for 100 g of the compound

N O

mass 46.7 g 53.3 g

number of 46.7 g/ 14 g/mol 53.3 g/ 16 g/mol

moles = 3.34 mol = 3.33 mol

divide by the least number of moles

3.34/3.33 = 1.00 3.33/ 3,33 = 1.00

therefore number of atoms are

N - 1

O - 1

empirical formula is - NO


mass of empirical unit - 14 g/mol + 16 g/mol = 30 g

molecular formula is actual composition of elements in the compound

molecular mass - 60.01 g/mol


number of empirical units = molecular mass / empirical unit mass

= 60.01 g/mol / 30 g = 2

there are 2 empirical units


2(NO)

molecular formula = N₂O₂


6 0
3 years ago
Aqueous solutions of barium nitrate and potassium phosphate are mixed. What is the precipitate and how many molecules are formed
kykrilka [37]

Aqueous solutions of barium nitrate and potassium phosphate are mixed. What is the precipitate and how many molecules are formed?

Barium nitrate has a chemical symbol of Ba(NO3)2 and potassium phosphate has a chemical symbol K2PO4. The reaction between these two is a double replacement reaction yielding barium phosphate and potassium nitrate.

The chemical equation representing the reaction is,

            Ba(NO3)2 + K2PO4 à KNO3 + BaPO4

8 0
3 years ago
Read 2 more answers
What limiting factor is climate considered
gtnhenbr [62]
Climate is considered an abiotic limiting factor because it is non living . hope this helped :))
6 0
3 years ago
Which of the following is an example of qualitative
vichka [17]

Answer:

Option =C each mouse in the study has brown ears.

Explanation:

Qualitative:

Qualitative properties are those that can be only observed but not measured in numerical values. These are observed through senses: touch, sight, smell, taste and hear.

For example:

Color, odor, brittleness, taste etc.

Quantitative:

Quantitative properties can be measured in numerical values.

For example:

Melting point, boiling point, conductivity, viscosity, density, hardness and solubility.

In short we can say that qualitative is a measure of quality while the quantitative is a measure of quantity.

4 0
3 years ago
Five ?L of a 10-to-1 dilution of a sample were added to 5mL of Bradford reagent. The absorbance at 595 nm was 0.78 and,according
Tomtit [17]

Answer:

0.03g/mL

Explanation:

Given parameters include:

Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL

Dilution factor = 10-to-1

The absorbance at 595 nm was 0.78

Mass of the diluted sample = 0.015 mg

We need to first determine the concentration of the diluted sample which is required in calculating the protein concentration of the original solution.

So, to determine the concentration of the diluted sample, we have:

concentration of diluted sample = \frac{mass}{volume}

= \frac{0.015 mg}{ 5 \alpha L}   (where ∝ was use in place of μ in the expressed fraction)

= 0.003 mg/μL

The dilution of the sample is from 10-to-1 indicating that the original concentration is ten times higher; as such the protein concentration of the original solution can be calculated as:

protein concentration of the original solution = 10 × concentration of the diluted sample.

= 10  × 0.003 mg/μL

= 0.03 mg/μL

= \frac{0.03*10^{-3g}}{10^{-3}mL}

= 0.03g/mL

Hence, the protein concentration of the original solution is known to be  0.03g/mL

8 0
3 years ago
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