Carbon-12 and Carbon-14 are isotopes of Carbon. Although they have the same number of protons, the <span>number of neutrons in each atom is not the same~</span>
Answer: An initial velocity
Explanation:
Answer:
2CO₂ ⇄ 2CO + O₂.
Explanation:
- <em>The equilibrium constant (Keq)</em> for a reaction is the ratio of the concentration of the products to the reactants, each one is raised to each molar coefficient.
So, for Keq = [CO]²[O₂]/[CO₂]²,
It is clear that the products are CO and O₂, while the reactant is CO₂.
So, the reaction for this is:
<em>2CO₂ ⇄ 2CO + O₂.</em>
I am assuming that this compound contains carbon, hydrogen and oxygen. The molar mass of carbon, hydrogen and oxygen is 12, 1 and 16 grams/mol. Given these molar mass we now need to know the number of C H and O in the compound. To have 132 the compound must be C6H12O3
Answer:
a. Boron trifluoride
b. Propane
c. Dinitrogen pentoxide
d. Carbon Dioxide
e. Silicon Octafluroride?
Explanation:
Glad to help :)
