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2 years ago

Look below giving Brainliest

Mathematics

1 answer:

scoundrel [369]2 years ago

6 0

Answer:

Not sure if you are looking for the area of the triangle, but I have attached a picture of me solving the triangle. Bothe of the equation are same. I would appreciate if you give me the brainlist or not, thank you :) !!

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Integrate dx/sin3xtan3x

disa [49]

$\displaystyle\int\frac{\mathrm dx}{\sin3x\tan3x}=\int\frac{\cos3x}{\sin^23x}$

Set $u=\sin3x$ , so that $\mathrm du=3\cos3x\,\mathrm dx$ . Then the integral is

$\displaystyle\frac13\int\frac{\mathrm du}{u^2}=-\frac1{3u}+C=-\frac1{3\sin3x}+C=-\frac13\csc3x+C$

Or, if you meant exponents in place of coefficients,

$\displaystyle\int\frac{\mathrm dx}{\sin^3x\tan^3x}=\int\csc^3x\cot^3x\,\mathrm dx=\int\csc^2x\cot^2x\csc x\cot x\,\mathrm dx$

Let $u=\csc x$ , so that $\mathrm du=-\csc x\cot x\,\mathrm dx$ , and use the fact that $\csc^2x=\cot^2x+1$ to get

$\displaystyle-\int u^2(u^2-1)\,\mathrm du=\int (u^2-u^4)\,\mathrm du=\frac13u^3-\frac15u^5+C$
$=\dfrac13\csc^3x-\dfrac15\csc^5x+C$

8 0

2 years ago

Please ignore the option that I clicked on, unless it is correct.

Kipish [7]

If 455 changes to a higher number the mean which is the average should increase to a higher number

3 0

2 years ago

Your cell phone plan gives you 500 minutes monthly. If you have used 310 minutes already and there is a week left in this month,

aksik [14]

The minutes remaining till the end of the month = 500 - 310 = 190 minutes
now to split these minutes equally, we will divide them by 7 days of week
daily usage = 190/7 = 27.14 minutes
since we can not talk for 0.14 minutes, therefore,to equally split the remaining minutes, you should speak 27 minutes per day with one extra minutes remaining to be used on the day you choose

8 0

2 years ago

Read 2 more answers

Consider a manufacturing process that is producing hypodermic needles that will be used for blood donations. These needles need

Mars2501 [29]

Answer:

$\text{Average diameter is 1.65 mm and we decide that it is not 1.65 mm.}$

Step-by-step explanation:

We are given the following in the question:

The needle size should not be too big and too small.

The diameter of the needle should be 1.65 mm.

We design the null and the alternate hypothesis

$H_{0}: \mu = 1.65\text{ mm}\\H_A: \mu \neq 1.65\text{ mm}$

Sample size, n = 35

Sample mean, $\bar{x}$ = 1.64 mm

Sample standard deviation, s = 0.07 mm

Type I error:

It is the error of rejecting the null hypothesis when it is true.
It is also known as false positive error.
It is the rejecting of a true null hypothesis.

Thus, type I error in this study would mean we reject the null hypothesis that the average diameter is 1.65 mm but actually the average diameters of the needle is 1.65 mm.

Thus, average diameter is 1.65 mm and we decide that it is not 1.65 mm.

8 0

2 years ago

Read 2 more answers

Charles is 20% heavier than Edith. If Charles weighs 60kg, what is Edith's weight?

ddd [48]

Charles' weight = Edith's weight + 20% of Edith's weight

We'll use a variable to represent Edith's weight, x.

The decimal form of 20% is 0.2.

60 = x + 0.2x

60 = 1.2x

x = 50

Edith's weight is 50kg.

Hope this helps!

4 0

1 year ago