Answer:
In physics, equations of motion are equations that describe the behavior of a physical system in terms of its motion as a function of time.[1] More specifically, the equations of motion describe the behaviour of a physical system as a set of mathematical functions in terms of dynamic variables. These variables are usually spatial coordinates and time, but may include momentum components. The most general choice are generalized coordinates which can be any convenient variables characteristic of the physical system.[2] The functions are defined in a Euclidean space in classical mechanics, but are replaced by curved spaces in relativity. If the dynamics of a system is known, the equations are the solutions for the differential equations describing the motion of the dynamics.
Answer:
ΔE = 37.8 x 10^9 J
Explanation:
The energy required will increased the potential energy and increase the kinetic energy.
As the altitude change is fairly small compared to the earth radius, we can ASSUME that the average gravity will be a good representative
Gravity acceleration at altitude would be 9.8(6400²/8000²) = 6.272 m/s²
G(avg) = (9.8 + 6.272)/2 = 8.036 m/s²
ΔPE = mG(avg)Δh = 1000(8.036)(8e6 - 6.4e6) = 12.857e9 J
The centripetal force at orbit must be equal to the gravity force
mv²/R = mg'
v²/8.0e6 = 6.272
v² = (6.272(8.0e6)) = 50.2e6 m²/s²
The maximum velocity when resting on earth at the equator is about 460 m/s.
The change in kinetic energy is
ΔKE = ½m(vf² - vi²)(1000)
ΔKE = ½(1000)(50.2e6 - 460²) = 25e9 J
Total energy increase is
25e9 + 12.857e9 = 37.8e9 J
Answer:
10,200 Cal. per day
Explanation:
The mouse consumes 3.0 Cal each day, and has a mass of 20 grams. We can use this data to obtain a ratio of energy consumption per mass
.
For the human, we need to convert the 68 kilograms to grams. We can do this with a conversion factor. We know that:
,
Now, we can divide by 1 kg on each side
,
.
Using this conversion factor, we can obtain the mass of the human in grams, instead of kilograms. First, lets take:
We can multiply this mass for the conversion factor, we are allowed to do this, cause the conversion factor equals 1, and its adimensional
Now that we know the mass of the human on grams, we can multiply for our ratio of energy consumption
So, we would need 10,200 Cal per day.
The formula to use is the one that connects the acceleration,
the distance fallen, and the time spent falling:
Distance = 1/2 a T² .
You said 2.1 meters in 0.6 second .
2.1 m = 1/2 a (0.6 sec)²
Multiply each side by 2 : 4.2 m = a (0.6 sec)²
Divide each side by (0.6 sec)² = (4.2/0.36) m/s² = a
a = (11 and 2/3) m/s²
(about 19% more than Earth's gravity)
Solution:
In this question we have given,
initial velocity,u = 0
final velocity, v = 1m/s
displacement =.5mm (Because 1mm=.001m)
We have to find
1.acceleration
2. Time
1. we know third equation of motion is given as,
............(1)
Put values of v,u and s in equation (1)
![[tex]s=1^{2} = 0^{2} +2X.0005Xa\\1= .001a\\therefore, a = 1/.001\\ a= 1000m/s^{2}](https://tex.z-dn.net/?f=%5Btex%5Ds%3D1%5E%7B2%7D%20%3D%200%5E%7B2%7D%20%2B2X.0005Xa%5C%5C1%3D%20.001a%5C%5Ctherefore%2C%20a%20%3D%201%2F.001%5C%5C%20a%3D%201000m%2Fs%5E%7B2%7D)
2. We know First equation of motion is given as
......................(2)
put values of v, u and a in equation(2)
