Question

If 2000 kg cannon fires 2 kg projectile having muzzle velocity 200 m/s then the KINETIC ENERGY of the projectile will be ("E4" means "*10^4") *
1 point
4E4 J
1E4 J
1E3 J
None of the above

Answer 1

Answer:

$K=4\times 10^4\ J$

Explanation:

Given that,

Mass of cannon is,M =  2000 kg

Mass of projectile, m = 2 kg

Velocity of the projectile, v = 200 m/s

We need to find the kinetic energy of the projectile. We know that the formula for the kinetic energy of an object is given by :

$K=\dfrac{1}{2}mv^2\\\\\text{Putting all the values, we get}\\\\K=\dfrac{1}{2}\times 2\times (200)^2\\\\K=40000\ J$

or

$K=4\times 10^4\ J$

So, the kinetic energy of the projectile will be $4\times 10^4\ J$.