The refrigerator's coefficient of performance is 6.
The heat extracted from the cold reservoir Q cold (i.e., inside a refrigerator) divided by the work W required to remove the heat is known as the coefficient of performance, or COP, of a refrigerator (i.e., the work done by the compressor). The required inside temperature and the outside temperature have a significant impact on the COP.
As the inside temperature of the refrigerator decreases, its coefficient of performance decreases. The coefficient of performance (COP) of refrigeration is always more than 1.
The heat produced in the cold compartment, H = 780.0 J
Work done in ideal refrigerator, W = 130.0 J
Refrigerator's coefficient of performance = H/W
= 780/130
= 6
Therefore, the refrigerator's coefficient of performance is 6.
Energy conservation requires the exhaust heat to be = 780 + 130
= 910 J
Learn more about coefficient here:
brainly.com/question/18915846
#SPJ4
Answer: Temperature and humidity are the two characteristics used to classify air masses.
Explanation:
Answer:
Single Compound
Explanation:
A synthesis reaction takes two or more reactants and reacts chemically to turn them all into one substance.
An example of a synthesis reaction is the reaction that takes place between sodium (Na) and chlorine (Cl) to create table salt.
Answer: 2.1 × 10^7 m/s
Explanation:
Please see the attachments below
The density of the object is approximately 1.91 kg per m³.
42 kg is a measure of mass, and 22 m³ is a measure of volume. Knowing this, you can use the relationship

to solve for the object's density.
42 kg

22 m³

1.91 kg per m³.