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Lapatulllka [165]
2 years ago
8

Sort the sequences based on type of mutation they display.

Chemistry
1 answer:
jarptica [38.1K]2 years ago
3 0

Answer:

There are three types of DNA Mutations: base substitutions, deletions and insertions. Single base substitutions are called point mutations, recall the point mutation Glu -----> Val which causes sickle-cell disease. Point mutations are the most common type of mutation and there are two types.

Explanation:

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If a solution has a pH of 2, what is the hydroxide ion concentration?
murzikaleks [220]

Answer:

A

Explanation:

14=pH + pOH

pOH= 14 - 2

pOH= 12

pOH= -log[OH]

[OH]= 10^-12

=1×10^-12

5 0
1 year ago
Why were colonists in new england angry at king james 2 abd governor edmund andros of new england?​
Pani-rosa [81]

His strict imposition of autocratic rule was supported by his appointment by the King, who otherwise was not directly involved.

Explanation:

Andros’ imposition of Episcopalian worship in the Old South Meeting house, Boston his vigorous enforcement of the Navigation Acts.

He had earned the enmity of the local populace by enforcing the restrictive Navigation Acts.

He had infuriated Puritans in Boston by promoting the Church of England, which was rejected by many Nonconformist New England colonists.

When news of the overthrow of James II (1688) reached Boston, the colonists revolted, deposing Andros and imprisoning him.

His requirement that landholders take out new land patents and his limitations upon town meetings and rights of local taxation all aroused sharp resentment in colonial America.

7 0
3 years ago
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mamaluj [8]
Number 1: (A.)
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3 0
3 years ago
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write the chemical formula for the following compound -magnesium chloride, zinc sulphide Sodium,sodium sulphate, calcium bicarbo
Sindrei [870]

Answer:

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6 0
3 years ago
Calculate the percentage of each element in acetic acid, hc2h3o2, and glucose, c6h12o6.
My name is Ann [436]
<em>Acetic acid, HC2H3O2</em>

First, calculate for the molar mass of acetic acid as shown below.
    M = 1 + 2(12) + 3(1) + 2(16) = 60 g

Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
    P1 = ((4)(1)/60)(100%) = <em>6.67%</em>

<em> Carbon:</em>
   P2 = ((2)(12)/60)(100%) = <em>40%</em>

<em>Oxygen</em>
  P3 =((2)(16) / 60)(100%) = <em>53.33%</em>

<em>Glucose, C6H12O6</em>

The molar mass of glucose is as calculated below,
   6(12) + 12(1) + 6(16) = 180

The percentages of the elements are as follow,
 <em> Hydrogen:</em>
   P1 = (12/180)(100%) = <em>6.67%</em>

<em>Carbon:</em>
  P2 = ((6)(12) / 180)(100%) = <em>40%</em>

<em>Oxygen:</em>
  P3 = ((6)(16) / 180)(100%) = <em>53.33%</em>

b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal. 
6 0
3 years ago
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