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3 years ago

9

Can someone show their work on how to do this: Calculate the number of moles of Al2O3 present in 23.87g. (Molar mass of Al2O3= 1

02.0g/mol)

1 answer:

vodomira [7]3 years ago

6 0

Answer:

0.234 moles

Explanation:

moles of Al2O3 = mass / molar mass

moles of Al2O3 = 23.87g / 102.0g/mol

moles of Al2O3 = 0.234 moles (to three significant figures)

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