Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Answer:
Decant means "to pour." Kids moving water back and forth between two cups, your dad pouring a bucket of soapy water in the sink, or a wine expert emptying a bottle of wine into a fancy glass container — all of them are decanting liquids.
Explanation:
Periodic trends are specific patterns that are present in the periodic table that illustrate different aspects of a certain element, including its size and its electronic properties. Major periodic trends include: electronegativity, ionization energy, electron affinity, atomic radius, melting point, and metallic character. Periodic trends, arising from the arrangement of the periodic table, provide chemists with an invaluable tool to quickly predict an element's properties. These trends exist because of the similar atomic structure of the elements within their respective group families or periods, and because of the periodic nature of the elements.
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Answer:</h3>
3.342 x 10^24 molecules of water
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Explanation:</h3>
Given;
Mass of water = 100.0 g
Required to determine the number of molecules in 100.0 g of water
Using Avogadro's constant
1 mole of a compound contains 6.022 × 10^22 molecules
Thus;
1 mole of H₂O contains 6.022 × 10^23 molecules
But;
1 mole = 18.02 g/mol
Therefore;
18.02 g of water contains 6.022 × 10^23 molecules
100.0 g of water will have;
= (100. 0 g ×6.022 × 10^23 molecules) ÷ 18.02
= 3.342 x 10^24 molecules
