1.65g MgO = 1g Mg
1.65 - 1 = 0.65 g of O in MgO
solve it using proportion:
1g Mg / 0.65g O = x (g) Mg / 16g O
or 1 / 0.65 = x / 16
24.6 g is the answer.
if 1 gram of oxygen requires 1.65 grams of Mg
then 16 grams of oxygen will require 16 ( 1.65) or 26.4 grams.
Answer:
melting point will be higher than that of pure ethyl acetate
Explanation:
Answer:
2 L
Explanation:
From the question given above, the following data were obtained:
Molarity of LiF = 2 M
Mole of LiF = 4 moles
Volume =?
Molarity of a solution is simply defined as the mole per unit litre of the solution. Mathematically, it is expressed as:
Molarity = mole / Volume
With the above formula, we can obtain the volume of the solution as shown below:
Molarity of LiF = 2 M
Mole of LiF = 4 moles
Volume =?
Molarity = mole / Volume
2 = 4 / volume
Cross multiply
2 × volume = 4
Divide both side by 2
Volume = 4/2
Volume = 2 L
Therefore, the volume of the solution is 2 L.
If you start with 40.0 grams of the element at noon, 10.0 grams
radioactive element will be left at 2 p.m. The correct answer between
all the choices given is the second choice or letter B. I am hoping that this
answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.
Control group: 50 dogs continuing their normal diet
Experiments group: 50 dogs chosen to eat the new food
Independent variable: dog food
Dependent variable: the dogs’ weight
