If T1=454 K and T2=356 K atm and V1=101.85 mL. then what is V2? please help asap!!!
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This problem is providing us with the mass (70 g), absorbed heat (96 J) and initial and final temperatures (293 K and 313 K, respectively) so the specific heat of the material is required and found to be 0.0686 J/(g*K) as shown below:
<h3>Calorimetry:</h3>
In chemistry, we can go over calorimetry by writing the following relationship among heat, mass, specific heat and temperature change:
Thus, one can get the specific heat by solving for C in the previous equation:
Hence, we can plug in the given data to obtain:
Learn more about calorimetry: brainly.com/question/1407669