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SVEN [57.7K]
3 years ago
15

What is the number of molecules of 140 g of CO2?

Chemistry
1 answer:
Nadya [2.5K]3 years ago
7 0

Answer:

We have been given a quantity of carbon monoxide, CO, which is 140 g. we have to find the number of molecules in this quantity of carbon monoxide. Hence, 140 g of CO has 3.02×1024molecules.

Explanation:

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calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w
kipiarov [429]

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is -22Jmole^-^1k^-^1

(b) The normal boiling point of water (J·K−1·mol−1) is -109Jmole^-^1K^-^1

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is  109J/mole

Explanation:

Lets calculate

(a) - General equation -

      (\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p = -5_m(\beta )+5_m(\alpha ) =  -\frac{\Delta H}{T}

 \alpha ,\beta → phases

ΔH → enthalpy of transition

T → temperature transition

 (\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p == -\frac{\Delta_fH}{T_f}

            = \frac{-6.008kJ/mole}{273.15K} ( \Delta_fH is the enthalpy of fusion of water)

           = -22Jmole^-^1k^-^1

(b) (\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}

                                  = \frac{40.656kJ/mole}{373.15K} (\Delta_v_a_p_o_u_rH is the enthalpy of vaporization)

                               = -109Jmole^-^1K^-^1

(c) \Delta\mu =\Delta\mu(l)-\Delta\mu(s) =-S_m\DeltaT

[\mu(l-5°C)-\mu(l,0°C)] =  [\mu(s-5°C)-\mu(s,0°C)]=-S_mΔT

\mu(l,-5°C)-\mu(s,-5°C)=-Sm\DeltaT [\mu(l,0

\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)

     = 109J/mole

6 0
3 years ago
I need help ASAP! How many reactants and products are in each element according to the chemical equation above.
Len [333]

Answer:

O 4

C 1

1 sodium

3 H

Products

1 sodium

3 H

4 O

1 C

Explanation:

7 0
3 years ago
Combustion of 6.90g of this compound produced 13.8g of CO2 and 5.64g of H2O. What is the empirical formula of the unknown compou
Alla [95]
The empirical formula for the unknown compound would be: C2H4O (2 molecules of Carbon, 4 molecules of Hydrogen, and 1 molecule of Oxygen)
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Describe the characteristics that all living<br> things share.
andriy [413]

Answer:

Order, sensitivity or response to the environment, reproduction, growth and development, regulation, homeostasis, and energy processing.

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2Ag2S + 2H2O—>4Ag+2H2S+O2

The reactants are silver sulphide (Ag2s) and water (H2O)
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