1/216 don’t forget to simplify
Answer:
(x+2)/(x-6)(x+2)
Step-by-step explanation:
We know that vertical asymptotes are found in the denominator, so we can start with 1/(x-6)
x-6 will equal zero at 6, so that is where the VA will be.
For the removable discontinuity (hole), it needs to cancel out in the numerator and denominator. (x+2)/(x-6)(x+2)
when x equals -2, there is an undefined y value.
what ones do you need help on?
20 and 2 they are coefficientsHHQHABDBR3838
Answer:
0.29
Step-by-step explanation:
Given :
n : ___ 0 _____ 1 ____ 2 ____ 3 ____ 4
P(n) : 0.82___ 0.11 ___0.04 _0.02 ___0.01
The expected number of defect in a shipment can be obtained using the expected value formula :
Expected value, E(X) = Σx*p(x)
Σx*p(x) = (0*0.82) + (1*0.11) + (2*0.04) + (3*0.02) + (4*0.01)
E(X) = 0.29
Hence, the expected number of defect in shipment is 0.29
