An "emergency blow" is a procedure used by military submarines to quickly rise to the surface in case of trouble. It involves us
ing compressed air to pump out ballast water from its tanks.Suppose the submarine SSN Cthulhu has a displacement volume when fully submerged of 32000 m3. It is submerged with neutral buoyancy at a periscope depth of 30m when an emergency arises disabling its propulsion and other critical systems.Neglecting the pumped air’s density (much lower than that of water) and water resistance, what mass of water would this submarine have to pump out suddenly to make it to the surface in 30 seconds?
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Answer:
Density of Sand is .
Explanation:
Given Empty Density bottle weighs 23.5gm(W=23.5gm)
Weight of bottle when completely filled water=48.4gm
So amount of water required to fill the bottle=Weight of bottle filled with water-W
Amount of water required to fill the bottle()=48.4gm-23.5gm
g
Since we know density of water and
We can calculate volume of empty space in the bottle(V).
V
V=
V=
V=24.9
Now bottle is partially filled with sand,and weight of bottle is ()36.5gm
So,
Amount of sand added ()=36.5-Weight of the bottle
=13g
After filling the bottle with water again,the weight of the bottle becomes (=56.5g)
Therefore,
amount of water added to the bottle of sand in grams = -36.5gm
amount of water added =56.5g-36.5g
amount of water added =20g
As the density of water = 1g/
Amount of water (in grams )=Volume of water occupied
20=volume of water added
Therfore volume of water added to the sand filled bottle()=20
As we know the total volume of the water bottle(V),
Volume of the sand occupied in the water bottle=V-
=24.9g-20g
=4.9g
We know,
Density=Mass/Volume
Therefore,
density of sand =
density of sand =
density of sand =