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Talja [164]
3 years ago
7

An "emergency blow" is a procedure used by military submarines to quickly rise to the surface in case of trouble. It involves us

ing compressed air to pump out ballast water from its tanks.Suppose the submarine SSN Cthulhu has a displacement volume when fully submerged of 32000 m3. It is submerged with neutral buoyancy at a periscope depth of 30m when an emergency arises disabling its propulsion and other critical systems.Neglecting the pumped air’s density (much lower than that of water) and water resistance, what mass of water would this submarine have to pump out suddenly to make it to the surface in 30 seconds?

Physics
1 answer:
sleet_krkn [62]3 years ago
7 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

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SCALCET8 3.9.018.MI. A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the
Firlakuza [10]

Answer:

The length of his shadow is decreasing at a rate of 1.13 m/s

Explanation:

The ray of light hitting the ground forms a right angled triangle of height H, which is the height of the building and width, D which is the distance of the tip of the shadow from the building.

Also, the height of the man, h which is parallel to H forms a right-angled triangle of width, L which is the length of the shadow.

By similar triangles,

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Also, when the man is 4 m from the building, the length of his shadow is L = D - 4

So, D - 4 = hD/H

H(D - 4) = hD

H = hD/(D - 4)

Since h = 2 m and D = 12 m,

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Since L = hD/H

and h and H are constant, differentiating L with respect to time, we have

dL/dt = d(hD/H)/dt

dL/dt = h(dD/dt)/H

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dL/dt = h(dD/dt)/H

dL/dt = 2 m(-1.7 m/s)/3 m

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5 0
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