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Alla [95]
3 years ago
15

Costom duty of 30 % is charged when electrical item are imported. If 9000 rupees has to be paid as customs duty when an item of

this type is imported .What is the value of the item which is being imported
Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer:

30,000 rupees

Step-by-step explanation:

Percentage of custom duty = 30%

Amount of custom duty = 9000 rupees

Let

x = value of the item which is being imported

30% of x = 9000 rupees

30/100 * x = 9000

0.3 * x = 9000

0.3x = 9000

x = 9,000/0.3

x = 30,000 rupees

x = value of the item which is being imported = 30,000 rupees

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Two linear equations are shown. A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFr
Lorico [155]

Answer:

(7,\frac{13}{3})

Step-by-step explanation:

we have

<em>The equation of the first line</em>

y=\frac{1}{3}x+2 ------> equation A

<em>The equation of the second line</em>

y=\frac{4}{3}x-5 ------> equation B

Solve the system of equations by elimination

Multiply equation A by -4 both sides

(-4)y=(-4)(\frac{1}{3}x+2)

-4y=-\frac{4}{3}x-8 --------> equation C

Adds equation B and equation C

y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}

<em>Find the value of x</em>

substitute the value of y

\frac{13}{3}=\frac{1}{3}x+2

\frac{1}{3}x=\frac{13}{3}-2

Multiply by 3 both sides

x=13-6

x=7

therefore

The solution to the system of equations is the point (7,\frac{13}{3})

5 0
3 years ago
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Step-by-step explanation:

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Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu
dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\Substituting the values

d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\

So the total distance travelled is 1031 feet.

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