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LUCKY_DIMON [66]
3 years ago
9

Which of the following equations describes the graph?​

Mathematics
1 answer:
Strike441 [17]3 years ago
5 0

Answer:

y = -2(x - .5)^2 - 2.5

Step-by-step explanation:

You first want to find the vertex of the parabola, which is found at (.5, -2.5)

You then want to add this to the function "y = x"

y = (x - .5) - 2.5

You would then notice this would need to be a quadratic formula, so you would add the squared to the equation, and make the leading coefficient negative because it is facing downwards.

y = -(x - .5)^2 - 2.5

Finally, you would notice that the graph has a y-intercept of -3. You can Vertically stretch the equation y a factor of 2 to finish the graph.

y = -2(x - .5)^2 - 2.5

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Answer:

b

Step-by-step explanation:

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For each gym membership sold, the gym keeps $42, and the employee who sold it gets $8. What is the commission the employee earne
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In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0
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Leni [432]

Answer:

x^3+5x^2+3x

Step-by-step explanation:

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(remember when dividing subtract the smaller exponent from larger exponent

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Answer:

Step-by-step explanation:

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