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2 years ago

5/7 + 2/3 Plz Answer

Mathematics

2 answers:

notka56 [123]2 years ago

8 0

Answer:

29/21

Step-by-step explanation:

5/7 = 15/21

2/3 = 14/21

Olenka [21]2 years ago

4 0

Answer:

1.38 or 1 and 1/7

Step-by-step explanation:

5/7 + 2/3

10/21 + 14/21= 24/21

then your have to divide 24 by 21 = 1 and 3/21

then simplify 1 1/7

does this help?

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(SAT Prep) How many distinct triangles are for which the lengths of the sides are 5,9 and n, where n is an integer and 10

Nana76 [90]

The answer is C because you can have a triangle with 5,9,n 5,10,n 9,10,n and 5,10,9

The reason why is because the sum of two sides is always larger than the value of the third side.

I hope that this helps.

7 0

3 years ago

Read 2 more answers

a parallelogram has a base of 3 feet and a height of 5 feet. The base and height will each be doubled. Will the area also be dou

navik [9.2K]

Answer:

No, doubling the base and height would actually quadruple the area,

Step-by-step explanation:

With the original measurements of b = 3 ft and h = 5 ft,

b x h = A

(3) x (5) = 15 ft

So lets say we doubled the factors:

(2)(3) x (2)(5) = A

We would end up with 60 feet, four times that of 15.

(6) x (10) = 60 ft

3 0

3 years ago

Solve the soultion .explian please x(2x- 5)=0

AysviL [449]

$x(2x-5)=0\iff x=0\ \vee\ 2x-5=0\\\\x=0\ \vee\ 2x=5\\\\x=0\ \vee\ x=\frac{5}{2}\\\\x=0\ \vv\ x=2.5$

7 0

3 years ago

Read 2 more answers

Work out the area of abcd. please ensure you give workings out too.

ipn [44]

Answer:

$\displaystyle A_{\text{Total}}\approx45.0861\approx45.1$

Step-by-step explanation:

We can use the trigonometric formula for the area of a triangle:

$\displaystyle A=\frac{1}{2}ab\sin(C)$

Where a and b are the side lengths, and C is the angle between the two side lengths.

As demonstrated by the line, ABCD is the sum of the areas of two triangles: a right triangle ABD and a scalene triangle CDB.

We will determine the area of each triangle individually and then sum their values.

Right Triangle ABD:

We can use the above area formula if we know the angle between two sides.

Looking at our triangle, we know that ∠ADB is 55 DB is 10.

So, if we can find AD, we can apply the formula.

Notice that AD is the adjacent side to ∠ADB. Also, DB is the hypotenuse.

Since this is a right triangle, we can utilize the trig ratios.

In this case, we will use cosine. Remember that cosine is the ratio of the adjacent side to the hypotenuse.

Therefore:

$\displaystyle \cos(55)=\frac{AD}{10}$

Solve for AD:

$AD=10\cos(55)$

Now, we can use the formula. We have:

$\displaystyle A=\frac{1}{2}ab\sin(C)$

Substituting AD for a, 10 for b, and 55 for C, we get:

$\displaystyle A=\frac{1}{2}(10\cos(55))(10)\sin(55)$

Simplify. Therefore, the area of the right triangle is:

$A=50\cos(55)\sin(55)$

We will not evaluate this, as we do not want inaccuracies in our final answer.

Scalene Triangle CDB:

We will use the same tactic as above.

We see that if we can determine CD, we can use our area formula.

First, we can determine ∠C. Since the interior angles sum to 180 in a triangle, this means that:

$\begin{aligned}m \angle C+44+38&=180 \\m\angle C+82&=180 \\ m\angle C&=98\end{aligned}$

Notice that we know the angle opposite to CD.

And, ∠C is opposite to BD, which measures 10.

Therefore, we can use the Law of Sines to determine CD:

$\displaystyle \frac{\sin(A)}{a}=\frac{\sin(B)}{b}$

Where A and B are the angles opposite to its respective sides.

So, we can substitute 98 for A, 10 for a, 38 for B, and CD for b. Therefore:

$\displaystyle \frac{\sin(98)}{10}=\frac{\sin(38)}{CD}$

Solve for CD. Cross-multiply:

$CD\sin(98)=10\sin(38)$

Divide both sides by sin(98). Hence:

$\displaystyle CD=\frac{10\sin(38)}{\sin(98)}$

Therefore, we can now use our area formula:

$\displaystyle A=\frac{1}{2}ab\sin(C)$

We will substitute 10 for a, CD for b, and 44 for C. Hence:

$\displaystyle A=\frac{1}{2}(10)(\frac{10\sin(38)}{\sin(98)})\sin(44)$

Simplify. So, the area of the scalene triangle is:

$\displaystyle A=\frac{50\sin(38)\sin(44)}{\sin(98)}$

Therefore, our total area will be given by:

$\displaystyle A_{\text{Total}}=50\cos(55)\sin(55)+\frac{50\sin(38)\sin(44)}{\sin(98)}$

Approximate. Use a calculator. Thus:

$\displaystyle A_{\text{Total}}\approx45.0861\approx45.1$

8 0

3 years ago

There are two calculus classes at your school. Both classes have a class average of 75.5. The first class has a standard deviati

Korvikt [17]

To compare the two classes, the Coefficient of Variation (COV) can be used. The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)

For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)

The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.

4 0

2 years ago