The derivitive of sec(x) is sec(x)tan(x)
find the slope at pi/3
sec(pi/3)=2
tan(pi/3)=√3
sec(x)tan(x) at x=pi/3 is 2√3
for slope=m and a point is (x1,y1)
the equation is
y-y1=m(x-x1)
slope=2√3
point=(pi/3,2)
equation is
y-2=2√3(x-pi/3)
Answer: I think the last option is the correct answer.
Step-by-step explanation:
Answer:
3x-4y=15
7x+y=4
Solve7x+y=4 for y:
7x+y=4
7x+y+−7x=4+−7x (Add -7x to both sides)
y=−7x+4
Step: Substitute −7x+4 for y in 3x−4y=15:
3x−4y=15
3x−4(−7x+4)=15
31x−16=15 (Simplify both sides of the equation)
31x−16+16=15+16 (Add 16 to both sides)
31x=31
(Divide both sides by 31)
x=1
Step: Substitute 1 for x in y=−7x+4:
y=−7x+4
y=(−7)(1)+4
y=−3(Simplify both sides of the equation)
Answer: x=1 and y=−3
Given:
V = 5x² + 15x + 2, the volume
h = 5x, the height
Let A = the area of the base.
Because V = Ah, therefore
A*(5x) = 5x² + 15x + 2
Answer: