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3 years ago

PLEASE HELPPP ASAP

Physics

1 answer:

vodomira [7]3 years ago

6 0

Answer:

F = 12.5N

Explanation:

Force (F) = Mass (m) x Acceleration (a)

F = ma

F = (2.5kg) x (5m/s^2)

F = 12.5N

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ASE (National Institute for Automotive Service Excellence) certified professionals must be retested every _______ years to keep

Bess [88]

Hi,

The correct answer is C. five

I hope I helped :)

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3 years ago

From the average distance of one of jupiter's moons to jupiter and its orbital period around jupiter, we can determine:

den301095 [7]

Answer: Jupiter's mass

Explanation:

From Kepler's third law:

$T^2=\frac{4\pi^2}{GM}a^3$

where T is the orbital period of a satellite, a is the average distance of the satellite from the Planet, M is the mass of the planet, G is the gravitational constant.

If the average distance of one of Jupiter's moons to Jupiter and its orbital period around Jupiter is given then mass of the Jupiter can be found:

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3 years ago

Read 2 more answers

5. A person fishing from a pier observes that four wave crests pass by in 7.0 s and estimates that the distance between two succ

TiliK225 [7]

Answer:

v= 1.71 m/s

Explanation:

Given that

Distance between two successive crests = 4.0 m

λ = 4 m

T= 7 sec

T is the time between 3 waves.

3 waves = 7 sec

1 wave = 7 /3 sec

So t= 7/3 s

We know that frequency f

f= 1/t= 3/7 Hz

Lets take speed of the wave is v

v= f λ

f=frequency

λ=wavelength

v= 3/7 x 4 = 12 /7

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3 0

3 years ago

The earth has a vertical electric field at the surface,pointing down, that averages 102 N/C. This field is maintained by various

Schach [20]

Answer:

$q = -461532.5 \ C$

Explanation:

From the question we are told that

The electric filed is $E = 102 \ N/C$

Generally according to Gauss law

=> $E A = \frac{q}{\epsilon_o }$

Given that the electric field is pointing downward , the equation become

$- E A = \frac{q}{\epsilon_o }$

Here $q$ is the excess charge on the surface of the earth

$A$ is the surface area of the of the earth which is mathematically represented as

$A = 4\pi r^2$

Where r is the radius of the earth which has a value $r = 6.3781*10^6 m$

substituting values

$A = 4 * 3.142 * (6.3781*10^6 \ m)^2$

$A =5.1128 *10^{14} \ m^2$

$q = -E * A * \epsilon _o$

Here $\epsilon_o$ s the permitivity of free space with value

$\epsilon_o = 8.85*10^{-12} \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

substituting values

$q = -102 * 5.1128 *10^{14} * 8.85 *10^{-12}$

$q = -461532.5 \ C$

6 0

3 years ago

A car traveling at 50 m/s comes to a stop in 5 seconds. What is the<br> acceleration of this car?

Alexandra [31]

Answer:10

Explanation:

You have to do speed divided by time so your answers 10

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2 years ago