Answer:
8 m/s²
Explanation:
Centripetal acceleration formula:
- a = v²/r
- where v = velocity and r = radius
As you can see, the mass of the yo-yo is not relevant to this problem.
We are given that the velocity of the yo-yo is 4 m/s.
The radius of the circle formed by the yo-yo on a 2-meter long string is 2 meters.
Substitute these known values into the equation.
- a = (4)²/2
- a = 16/2
- a = 8
The centripetal acceleration of the yo-yo is 8 m/s².
Answer:
The value of final velocity of the first hockey puck 2.3
Explanation:
Mass of hockey puck = m
Initial velocity
From conservation of momentum principal
4.5 m = m + m × × 3.5
= 1.5
0 = m + m × × 3.5
= - 1.75
Now final velocity of first puck
Put the values in above formula we get
2.3
This is the value of final velocity of the first hockey puck.
Hello!
Distance of R/2:
Since a conducting sphere is referenced in this situation, all of its charge will be distributed along its SURFACE. Therefore, there is NO enclosed at a distance of R/2 from the center.
Using Gauss's Law:
E = Electric field strength (N/C)
A = Area of Gaussian surface (m²)
Q = Enclosed charge (C)
ε₀ = Permittivity of free space C²/Nm²)
If the enclosed charge is 0, then:
Distance of '2R':
We can once again use Gauss's Law to solve. This time, however, a surface of radius '2R' encloses ALL of the charge of the sphere.
'A' is equivalent to the surface area of a sphere of radius '2R', or:
Substituting this expression back into Gauss's Law:
To simplify:
OR using k = 1/4πε₀: