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2 years ago

4.) What is the area of this shape?

Mathematics

2 answers:

lys-0071 [83]2 years ago

6 0

Answer:

1456 square units

Step-by-step explanation:

The shape can be considered as the combination of a square with the side of 28 and a triangle with base of (28 + 10 + 10) and the height of 28

Then the area of the shape is:

28*28 + 1/2*48*28 =
784 + 672 =
1456 square units

Neporo4naja [7]2 years ago

5 0

Answer:

Its blurry, can you take another picture?

Step-by-step explanation:

You might be interested in

Select the best answer for the question.

nekit [7.7K]

B because absolute value means that the number inside the absolute value brackets is the positive version of the number

8 0

2 years ago

Is (3,-2) a solution to the system below? How do you know?

cricket20 [7]

Step-by-step explanation:

you know by using the x and y coordinates of the point in the equations and see, if both equations are still true.

if yes, it was a solution, and if just only one is false, then it was not a solution.

(3, -2) in

y + 4x = 10

5x - y = 13

so,

-2 + 4×3 = 10

-2 + 12 = 10

10 = 10 true

5×3 - (-2) = 13

15 + 2 = 13

17 = 13 false

so, it was NOT a solution.

3 0

1 year ago

Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a const

Vilka [71]

Answer:

Alison wins against Kevin by 0.93 s

Step-by-step explanation:

Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration $a_a$ , we have the following equation of motion

$s/4 = a_at_a^2/2$

where s (m) is the total distance, ta = 3 s is the time

$s = 4a_a3^2/2 = 18a_a$

$a_a = s/18$

Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration $a_k$ , we have the following equation of motion:

$s/3 = a_kt_k^2/2$

tk = 4 s is the time

$s = 3a_k4^2/2 = 24a_k$

$a_k = s/24$

Since $a_a = s/18$ we can conclude that $a_a > a_k$ , so Alison would win.

The time it takes for Alison to cover the entire track

$s = a_aT_a^2/2$

$T_a^2 = 2s/a_a = 2s/(s/18) = 36$

$T_a = \sqrt{36} = 6 s$

The time it takes for Kevin to cover the entire track

$s = a_kT_k^2/2$

$T_k^2 = 2s/a_k = 2s/(s/24) = 48$

$T_a = \sqrt{48} = 6.93 s$

So Alison wins against Kevin by 6.93 - 6 = 0.93 s

4 0

2 years ago

Lowest denominator 1/15 9/5 3/8

Stels [109]

LCD(115, 95, 38) = LCM(15, 5, 8) = 23×3×5 = 120
115 = 812095 = 21612038 = 45120

3 0

2 years ago

Read 2 more answers

In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day

nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

$P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33$

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

$P(A \cap B) = 0.42*0.25 = 0.105$

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

$P(B|A) = \frac{0.105}{0.33} = 0.3182$

31.82% probability that this day would be a winter day

6 0

2 years ago

4.) What is the area of this shape?​

4.) What is the area of this shape?