Recall that
where 
and 
are the lion's initial and final vertical velocities, 
is its acceleration, and 
is the vertical displacement.
At its maximum height, the lion has 0 vertical velocity, so we have
where <em>g</em> is the acceleration due to gravity, 9.80 m/s², and we take the starting position of the lion on the ground to be the origin so that 
.
Let <em>v</em> denote the initial speed of the jump. Then
Answer:
Length of the string = 0.24 m
Explanation:
The frequency (f) of vibration of stringed instruments is related to the Tension (T) in the spring by the relation
fₙ = (n/2L)√(T/μ)
where n = 1,2,3,4...
For third harmonic frequency, n = 3
L = length of the string = ?
T = tension in the string = 2.3 N
μ = linear density = 4.6 × 10⁻³ kg/m
f = frequency = 140 Hz
L = (n/2f)√(T/μ)
L = (3/(2×140))√(2.3/0.0046) = 0.40 m
Answer:
0.15694 m
Explanation:
m = Mass of block = 
v = Velocity of block = 11.2 m/s
k = Spring constant = 110 N/m
Here the kinetic energy of the fall and spring are conserved
The amplitude of the resulting simple harmonic motion is 0.15694 m
