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lana [24]
3 years ago
10

Based on this picture and your knowledge of the Pythagorean Theorm, what is the ara of the empty square?

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Answer:

100 units^2

Step-by-step explanation:

a^2+b^2=c^2

8^2+6^2=c^2

64+36=c^2

100=c^2 (area of square)

10=c (length of hypotenuse)

Therefore, the area of the square is 100 units^2

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Can someone explain to me why I should have used the point (-2, 4) for this equation instead of (-7. -3)?
Lady_Fox [76]
I dont know what this could be
8 0
3 years ago
Help please jggvnhujff
saveliy_v [14]

Answer:

Step-by-step explanation:

<u><em>8).</em></u>  \left \{ {{4x+3y=1} \atop {x+y=2}} \right.

<em>(2)</em> × [ - 3 ]

4x + 3y = 1 ........ <em>(3)</em>

- 3x - 3y = - 6 .... <em>(4)</em>

<em>(3)</em> + <em>(4)</em>

x = - 5

- 5 + y = 2 ⇒ y = 7

<em>( - 5 , 7 )</em>

<u><em>9).</em></u> \left \{ {{-9x+3y=18} \atop {2x+y=-4}} \right.

<em>(1)</em> ÷ [- 3]

3x - y = - 6  ......... <em>(3)</em>

2x + y = - 4 ........ <em>(4)</em>

<em>(3)</em> + <em>(4)</em>

5x = - 10 ⇒ x = - 2

2(- 2) + y = - 4 ⇒ y = 0

<em>(- 2, 0)</em>

<u><em>10).</em></u> \left \{ {{x-2y=14} \atop {10x-6y=0}} \right.

<em>(2)</em> ÷ 10

x - 0.6y = 0 ⇒ x = 0.6y -----> <em>(1)</em>

0.6y - 2y = 14

- 1.4y = 14

y = - 10

x - 2(- 10) = 14 ⇒ x = - 6

<em>(- 6, - 10)</em>

Now is your turn, you can do it!!

3 0
3 years ago
Help on this pleasee
Zina [86]

Answer: 40 degrees

Step-by-step explanation:

4 0
3 years ago
Divide 1.20m in the ratio 2:3:4 in a clear way
tatuchka [14]
2:3:4 gives 9 equal parts.
1.20 divided by 9 is 0.133.

2 * 0.133 would be 0.266m
3 * 0.133 would be 0.399m
4 * 0.133 would be 0.533m

To check this calculate 0.533 + 0.399 + 0.266 would be 1.198m (close enough)
4 0
4 years ago
What is the inverse of x^2-4x+5
lisabon 2012 [21]

we are given

f(x)=x^2-4x+5

Since, we have to find inverse of this function

step-1: we set f(x)=y

y=x^2-4x+5

step-2: switch x and y

x=y^2-4y+5

step-3: Solve for y

y^2-4y+(5-x)=0

now, we can use quadratic formula

y=\frac{4+\sqrt{4^2-4(5-x)} }{2}

f^{-1}(x)=\sqrt{x-1}+2

or

f^{-1}(x)=-\sqrt{x-1}+2..............Answer

6 0
3 years ago
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