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2 years ago

Line segment AB is the diameter of a circle. Find the center of the circle if:

Mathematics

2 answers:

Wittaler [7]2 years ago

5 0

The center of the circle is (-3,9/2)

katovenus [111]2 years ago

4 0

Answer:

$midpoint = \frac{-1 + -5}{2} , \frac{7+ 2}{2}$

(-3, $\frac{9}{2\\}$ ) is the center of the circle

Step-by-step explanation:

You use the midpoint of the two point given to us.

Hope this helped

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Classify the system and determine the number of solutions. Check all that apply. {7x + y = 13 28x + 4y = -12 A) inconsistent B

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3 years ago

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3 years ago

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3 years ago

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Write the expression for the following the product of five and two ,added to seven. PLS HELP ME

netineya [11]

Answer:

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Step-by-step explanation:

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2 years ago

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Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all

Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that $p = 0.95$

Find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

This is P(X = 2) when n = 4. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135$

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

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2 years ago