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vfiekz [6]
2 years ago
11

Solve for Voltage

Chemistry
1 answer:
vladimir1956 [14]2 years ago
7 0

Answer:

110V

Explanation:

Given parameters:

Current in the lightbulb  = 0.5A

Resistance  = 220Ω

Unknown:

Voltage  = ?

Solution:

To solve this problem, we apply the equation derived from ohm's law;

          V  = IR

So,

       V = 0.5 x 220  = 110V

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During the Big Bang, what were the two main chemical elements created?
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During the big band only the lightest elements were formed – hydrogen<span> and </span>helium<span> along with trace amounts of </span>lithium<span> and </span>beryllium<span>.</span>
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3 years ago
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An element has a half-life of 30 years. if 1.0 mg of this element decays over a period of 90 years, how many mg of this element
labwork [276]

Answer:

144.6

Explanation:

6 0
3 years ago
An energy of 6.8 x 10^-19 J/atom is required to cause an aluminum atom on a metal surface to lose an electron.
Nana76 [90]

Wavelength of the light is 2.9 × 10⁻⁷ m.

<u>Explanation:</u>

Planck - Einstein equation shows the relationship between the energy of a photon and its frequency, and they are directly proportional to each other and  it is given by the equation as E = hν,

where E is the energy of the photon

h is the Planck's constant = 6.626 × 10⁻³⁴ J s

ν is the frequency

From the above equation, we can find the frequency by rearranging the equation as,

ν = $ \frac{E}{h} = $ \frac{6.8 \times 10^{-19}}{6.626\times10^{-34}} = 1.03\times10^{15} s^{-1}

Now the frequency and the wavelength are in inverse relationship with each other.

ν × λ = c

It can be rearranged to get λ as,

λ = c / ν

 = $\frac{3\times 10^{8} ms^{-1}}{1.03\times10^{15}s^{-1}} = 2.9\times 10^{-7} m

So wavelength is 2.9 × 10⁻⁷ m.

6 0
3 years ago
P.1 is a variant of SARS-CoV2. This is the so-called "Brazil variant". It has the amino acid the substitution N501Y in the spike
Free_Kalibri [48]

Answer:

more negative

Explanation:

There are various variants of Coviid virus. The Brazilian variant P also known as Gamma variant is the third variant of the original SARS-CoV2. This variant has raised concerns since it has ability to spread more quickly then previous variants and this is more negative variant. It is assumed that Coviid variant Gamma and Delta has ability to absorb move UV light but this is not proved yet and research is underway.

7 0
3 years ago
What would be the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg?
Anna [14]

Answer: The temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 2300 mm Hg = 3.02 atm  (760mmHg=1atm)

V = Volume of gas = 15 L

n = number of moles = 0.6

R = gas constant =0.0821Latm/Kmol

T =temperature = ?

T=\frac{PV}{nR}

T=\frac{3.02atm\times 15L}{0.0821Latm/K mol\times 0.6mol}=920K

Thus the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

8 0
3 years ago
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