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asambeis [7]
2 years ago
5

A student cleaned their glassware with tap water (known to contain chloride ions). They then attempted to make a 0.020 M solutio

n of silver nitrate from a stock solution of 0.10 M silver nitrate and immediately noticed a white precipitate. Write the net ionic equation for the formation of the precipitate. Include states of matter.
Chemistry
1 answer:
Rina8888 [55]2 years ago
4 0

Answer:

Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

Explanation:

The silver nitrate, AgNO₃, dissolves in water as follows:

AgNO₃(aq) → Ag⁺(aq) + NO₃⁻(aq)

The Ag⁺ reacts with Cl⁻ producing AgCl(s), a white insoluble salt. The net ionic equation that describes the formation of the precipitate is:

<h3>Ag⁺(aq) + Cl⁻(aq) → AgCl(s)</h3><h3 /><h3 />
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The density of ethanol is 0.789 g/cm^3 at 20 degrees C. What volume of ethanol has a mass of 15.5 grams?
lys-0071 [83]
<span>density = mass / volume
   
given the quotient , we have density and mass, volume can be easily calculated as:
   
volume = mass / p =15.5 g / 0.789 g/cm^3
   
=~ 20 cm^3 (dimension ally constant)</span>
6 0
3 years ago
An object on top of a building has a GPE of 23,048j and a mass of 39kg, What is the height of the object
kirill115 [55]

Answer:

<h2>59.1 m</h2>

Explanation:

The height of the object can be found by using the formula

h =  \frac{p}{mg }  \\

where

p is the potential energy

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

h =  \frac{23048}{39 \times 10}  =  \frac{23048}{390}  \\  = 59.0974...

We have the final answer as

<h3>59.1 m</h3>

Hope this helps you

3 0
2 years ago
How are energy and the amplitude of a wave related?
castortr0y [4]

Answer:

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8 0
3 years ago
Can someone please help me with this I need help asap
DiKsa [7]

Answer:

???

Explanation:

6 0
2 years ago
Question 3 0
Tanya [424]

Answer:

Option D. KBr < KCl < NaCl

Explanation:

We'll begin by calculating the number of mole of each sample.

This can be obtained as follow:

For NaCl:

Mass = 1 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 1/58.5

Mole of NaCl = 0.0171 mole

For Kbr:

Mass = 1 g

Molar mass of KBr = 39 + 80 = 119 g/mol

Mole of KBr =?

Mole = mass /Molar mass

Mole of KBr = 1/119

Mole of KBr = 0.0084 mole

For KCl:

Mass = 1 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1/74.5

Mole of KCl = 0.0134 mole

Summary

Sample >>>>>>>> Number of mole

NaCl >>>>>>>>>> 0.0171

KBr >>>>>>>>>>> 0.0084

KCl >>>>>>>>>>> 0.0134

Arranging the number of mole of the sampl in increasing order, we have:

KBr < KCl < NaCl

5 0
3 years ago
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