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3 years ago

Atmospheric pressure is greater at the base of a mountain than at

1 answer:

8 0

At the top of the mountain, when he tightens the cap onto the bottole, there is some water and some air inside the bottle. Then he brings the bottle down to the base of the mountain.

The pressure on the outside of the bottle is greater than it was when he put the cap on. If anything could get out of the bottlde, it would. But it can't . . . the cap is on too tight. So all the water and all the air has to stay inside, and anything that can get squished into a smaller space has to get squished into a smaller space.

The water is pretty much unsquishable.

Biut the air in there can be <em>COMPRESSED</em>. The air gets squished into a smaller space, and the bottle wrinkles in slightly.

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Describe the phases of the moon along with a picture.

Alex787 [66]

Answer:

The eight Moon phases:

Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.

The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.

<h2>The 8 phases (in order) are:</h2>

New moon.
Waxing Crescent.
First Quarter.
Waxing Gibbous.
Full moon.
Waning Gibbous.
Third Quarter.
Waning Crescent.

Explanation:

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5 0

3 years ago

Read 2 more answers

What is the coefficient of friction between the skates and the ice?

natta225 [31]

The coefficient of friction is 0.051

Explanation:

The motion of the skater is a uniformly accelerated motion, therefore we can use the following suvat equation:

$v^2 - u^2 = 2as$

where:

v = 0 is the final velocity of the skater (he comes to a stop)

u = 10.0 m/s is his initial velocity

a is the acceleration

$s=1.0\cdot 10^2 m = 100 m$ is the distance he travels before stopping

Solving for a, we find the acceleration of the skater:

$a=\frac{v^2-u^2}{2s}=\frac{0-10.0^2}{2(100)}=-0.5 m/s^2$

We also know that the net force acting on the skater is the force of friction, therefore we can write (Newton's second law of motion):

$F= ma = -\mu mg$

where

$-\mu mg$ is the force of friction

m is the mass of the skater

$\mu$ is the coefficient of friction

$a=-0.5 m/s^2$ is the acceleration

$g=9.8 m/s^2$ is the acceleration of gravity

Solving for $\mu$ , we find the coefficient of friction:

$\mu = -\frac{a}{g}=-\frac{-0.5}{9.8}=0.051$

Learn more about friction:

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#LearnwithBrainly

8 0

3 years ago

A large room in a house holds 947 kg of dry air at 33.2°C. A woman opens a window briefly and a cool breeze brings in an additio

BartSMP [9]

Answer:

31.96362 °C

Explanation:

$m_1$ = Mass of air in the room = 947 kg

$m_2$ = Mass of air entering the room = 62.4 kg

$T_1$ = Temperature in the room = 33.2°C

$T_2$ = Temperature air entering the room = 13.2°C

T = Equilibrium temperature

c = Specific heat of air = 1006 J/kg °C

In the case of thermal equilibrium we have the relation

$m_1c(T_1-T)=m_2c(T-T_2)\\\Rightarrow T=\frac{m_2T_2+m_1T_1}{m_1+m_2}\\\Rightarrow T=\frac{62.4(13.2+273.15)+947(33.2+273.15)}{947+62.4}\\\Rightarrow T=305.11362\ K=305.11362-273.15=31.96362^{\circ}C$

The temperature of thermal equilibrium is 31.96362 °C

7 0

3 years ago

A ball of mass 6.00 kg moving with a

cestrela7 [59]

Answer: v=8,7m/s

Explanation:

Quando dois corpos andam aglutinados, significam que têm a mesma velocidade, e a quantidade de movimento antes de uma colisão, é igual á quantidade de tempo depois dessa colisão

4 0

3 years ago

As altitude increases, what happens to air pressure?

Mashcka [7]

Answer:

It decreases

Explanation:

The air pressure tends to be higher on the places with the lowest altitudes, and lower at the places with higher altitudes. Basically, the air pressure is the wight of the air, and since the air is denser and heavier at the lower altitudes, the air pressure is higher, while on the higher altitudes the air is less dense, thus the air pressure is lower. So in practice we can expect that the air pressure in a low valley will be higher than the air pressure at the top of higher mountain.

3 0

3 years ago

Read 2 more answers