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iren [92.7K]
3 years ago
14

What mass of aluminum nitrate do you need to prepare 3.58L of a 1.77M Solution?​

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
8 0
You need a mass of 177
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How does kinetic energy transform into potential energy?
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Kinetic energy is converted to potential energy because while it is not actually doing work, it has the potential to do work. If we drop the object from the shelf or release the spring, that potential energy is converted back into kinetic energy.
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Which element easily gains one electron to form a negative ion?
slava [35]

Answer:

B. Fluorine (F) element easily gains one electron to for a negative ion.

7 0
3 years ago
If the kb of a weak base is 1.1 × 10-6 m, what is the ph of a 0.49 m solution of this base?
Elden [556K]
When Kb = 1.1 x 10^-6

∴ Ka = Kw / Kb

        = 1.1 x 10^-14 / (1.1 x 10 ^-6) 

       = 1 x 10^-8

when the reaction equation when we assume the base is B

B + H2O ↔ BH+   + OH-

∴ Ka = [BH+][OH-]/[B]

1 x 10^-8 = X^2 / 0.49

X^2 = 4.9 x 10^-9

∴X = 7 x 10^-5

∴[OH-] = 7 x 10^-5

∴POH = -㏒[OH]

           = -㏒7 x 10^-5

           = 4.15

∴ PH = 14 - POH

             14 - 4.15

         = 9.85




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3 years ago
Cells that identify pathogens and distinguish one from another are called
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Lymphocytes, this is the white blood cell that identifies these pathogens

4 0
4 years ago
Calculate how many grams of hydrogen can be burned if 40. liters of oxygen at 200. k and 1.0 atm. show work pls.
Wittaler [7]

The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.

<h3>How do we calculate grams from moles?</h3>

Grams (W) of any substance will be calculated by using their moles (n) through the following equation:

  • n = W/M, where

M = molar mass

And moles of the gas will be calculated by using the ideal gas equation as:

  • PV = nRT, where

P = pressure = 1atm

V = volume = 40L

n = moles = ?

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature = 200K

On putting these values on the above equation, we get

n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles

  • Now grams of hydrogen gas will be calculated by using the first equation as:

W = (2.44mol)(2g/mol) = 4.88g

Hence required mass of hydrogen gas is 4.88g.

To know more about ideal gas equation, visit the below link:

brainly.com/question/15046679

#SPJ1

7 0
2 years ago
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