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iren [92.7K]
3 years ago
14

What mass of aluminum nitrate do you need to prepare 3.58L of a 1.77M Solution?​

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
8 0
You need a mass of 177
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In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol). Calculate the number of moles of chl
Annette [7]

Answer:

3.67 mol Cl

Explanation:

We need to convert g of Cl 2 to moles of Cl. First we divide 130 gCl2  by the molar mass (70.90 gCl2/mol) to find out how many moles of Cl2 do we have.

130 gCl2 x \frac{1 mol Cl2 }{70.90 gCl2} = 1.83 mol Cl2

Then we need to convert 1.83 mol de Cl2 to moles of Cl. We have 2 moles of Cl in every Cl2 molecule so we just need to multiply by 2.

1.83 molCl2 x \frac{2 molCl}{1 molCl2} = 3.67 molCl

8 0
3 years ago
Read 2 more answers
Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products.
UNO [17]

Explanation:

Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:

Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.

Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.

However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.

Elimination of the hydrogen from the methyl group is easier.

Thus, the major product will A

4 0
3 years ago
Using the Periodic Table, Which of the following has the largest atomic radius/size?
soldier1979 [14.2K]

Answer:

vp jokhimon vf dpp gl fl vk hggjuvg7vvohohohohojj

6 0
3 years ago
what mass of carbon dioxide gas would be produced if 10g of calcium carbonate reacted with an excess of hydrochloric acid?
LuckyWell [14K]
Answer is: 4,4 grams <span>of carbon dioxide gas would be produced.
</span>Chemical reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.
m(CaCO₃) = 10 g.
n(CaCO₃) = 10 g ÷ 100 g/mol.
n(CaCO₃) = 0,1 mol.
From chemical reaction: n(CaCO₃) : n(CO₂) = 1 : 1.
n(CO₂) = 0,1 mol.
m(CO₂) = n(CO₂) · M(CO₂).
m(CO₂) = 0,1 mol· 44 g/mol.
m(CO₂) = 4,4 g.
7 0
3 years ago
Silver was precipitated and collected by filtration. The experiment yielded .077g of silver after dying. The predicted yield was
PSYCHO15rus [73]

Answer:

Precentage error = 7.23%

Explanation:

The precentage error formula  is the  useful method  for determining precision of your experimental result

It can be calculated using :

percent\ error = |\frac{experimental\ value-predicted\ value} {predicted\ value}|\times 100

percent\ error = |\frac{0.077\ -0.083} {0.083}|\times 100

So we get percentage error =  7.23%

Precision means how close the experimental value to the true value or theoretical value

If percentage error is large it means experimental results are deviated and there is need to check mistakes,imprecision in the experiment

If the percentage error is zero it means the experiment is perfectly done without  inaccuracy

4 0
3 years ago
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