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oksano4ka [1.4K]
1 year ago
12

Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(

b) MnCl₂.
Chemistry
1 answer:
likoan [24]1 year ago
8 0

Balanced Half reactions are:

At anode 2Cl^{-}  ==> Cl₂+ 2e^{-} + H₂O ==> ClO^{-}+ 2H^{+} + Cl^{-}

At Cathode:  2H^{+} + 2e^{-} ==> H₂

Since the question states that you are using an aqueous solution of MnCl₂,  so ions will have present are, H₂O, H^{+}, Mn^{2+} and Cl^{-}

Now at Anode reaction will occur as given:

2Cl^{-}  ==> Cl₂+ 2e^{-} + H₂O ==> ClO^{-}+ 2H^{+} + Cl^{-}  (will occur)

At Cathode:

2H^{+} + 2e^{-} ==> H₂ (will occur)

At Cathode:

Mn^{2+} +  2e^{-}==> Mn (This reaction will not occur)

The deposition of solid Mn will not occur because in aqueous solution, H^{+}will be reduced before Mn^{2+} .

The reduction potentials for H^{+} is zero whereas reduction potential for Mn^{2+} is - 1.18V.

The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.

To learn more about the half reaction please click on the link brainly.com/question/13186640

#SPJ4

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Please answer both questions.
Deffense [45]

Answer:

1)Krypton

2)11H

Explanation:

electrons=protons

protons=atomic number

mass number=protons+neutrons

mass number is the superscript

atomic number is the subscript.

1)The answer is Krypton because its atomic number= number of protons=number of electrons is 36.

mass number is 46+36=82.

2)subscript=atomic number=number of protons=number of electrons

i. H = electrons=1

=neutrons=0

ii. Cl=electrons=17

=neutrons=35-17=18

iii. Na=electrons=11

=neutrons=23-11= 12

so the answer is Hydrogen because it has 1 electron and 0 neutron.

I hope this helps.

6 0
2 years ago
The equation for the reaction between copper and nitric acid is vCu + wHNO3--->xCu(NO3)2 + yNO + zH2O Balance the equation an
lana [24]

Answer:

The coefficients of the balanced equation are:

  • v= 1
  • w= 4
  • x= 1
  • y= 2
  • z=2

Explanation:

The Law of Conservation of Matter, also called the Law of Conservation of Mass or the Lomonósov-Lavoisier Law, postulates that "mass is neither created nor destroyed, it is only transformed". This means that the reagents interact with each other and form new products with different physical and chemical properties than the reagents, but the amount of matter or mass before and after a transformation (chemical reaction) is always the same. In other words, then the mass before the chemical reaction is equal to the mass after the reaction.

Then, you must balance the following chemical equation:

v Cu + w HNO₃ → x Cu(NO₃)₂ + y NO + z H₂O

For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts

  • Left side:   1 copper, 1 hydrogen, 1 nitrogen and 3 oxygen.
  • Right side:  1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Generally, hydrogen and oxygen balance in the end. So you balance nitrogen first, because copper is already balanced (there is the same amount on both sides of the reaction). If w = 2, then:

  • Left side:   1 copper, 2 hydrogen, 2 nitrogen and 6 oxygen.
  • Right side:  1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

But you see then that the oxygen is unbalanced and you have less quantity in the reagents. Then w must be greater. Being w = 4:

  • Left side:   1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
  • Right side:  1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

Going back to the idea of ​​balancing nitrogen, being y = 2:

  • Left side:   1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
  • Right side:  1 copper, 2 hydrogen, 4 nitrogen and 9 oxygen.

Balancing the hydrogen, being z = 2:

  • Left side:   1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
  • Right side:  1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.

Since you have the same amount of each element on each side of the reaction, the reaction is balanced. Then, the balanced equation is:

Cu + 4 HNO₃ → Cu(NO₃)₂ +  2 NO + 2 H₂O

Finally:

  • <u><em>v= 1</em></u>
  • <u><em>w= 4</em></u>
  • <u><em>x= 1</em></u>
  • <u><em>y= 2</em></u>
  • <u><em>z=2</em></u>
6 0
2 years ago
Bluebirds and blue jays, two bird species live in a small wooded area. The blue jays are very aggressive and eventually take ove
Dahasolnce [82]

Answer:

yes

Explanation:

it affects the bluebirds habitat

5 0
3 years ago
5-Methylcyclopentadiene undergoes homolytic bond cleavage of a C—H bond to form a radical that exhibits five resonance structure
AURORKA [14]

Answer: it forms cyclopentadienyl radical by homolysis. Allylic 3° free radical is more stable due to resonance

Explanation:

4 0
2 years ago
How many grams of lead (ll) sulfate would be produced from the complete reaction of 23.6 g lead (iV) oxide ?
djverab [1.8K]

Answer:

29.92grams of PbSO4

Explanation:

lead (iV) oxide = PbO2 = Molar mass: 239.2 g/mol

lead (ll) sulfate = PbSO4 = Molar mass: 303.26 g/mol

PbO2 = PbSO4

1:1 ratio

Pb = Lead

Lead has an oxidation number of 4+

O = Oxygen

Oxygen has an oxidation number of 2-

PbO2 + 4H+ + SO4 2- + 2e- = PbSO4(s) + 2H2O

Ok so the above would be the likely complete reaction, though we don't really need this as we already know the ratio is 1:1.

23.6g of PbO2

23.6/239.2 = 0.09866 Moles of PbO2

Since we have a 1:1 ratio we know that the same number of moles of PbSO4 are produced and since we know the molar mass it's simply molar mass multiplied by number of moles.

303.26 x 0.09866 = 29.92grams of PbSO4

6 0
3 years ago
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