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Scrat [10]
3 years ago
6

Which of the following are state functions?: Temperature, Enthalpy, Exergy, Internal Energy, Adiabatic Work, Heat (2 marks) b) P

rovide definitions for the following terms: i) Reversible process ii Ethalpy iii Entropy iv) Internal energy v) Isentropic process v) Adiabatic
Chemistry
2 answers:
Reika [66]3 years ago
6 0

Answer:

a) The state functions are: internal energy, temperature, enthalpy and exergy.

b) Definitions of terms are found in the explanation section.

Explanation:

a) The state functions are those quantities that are used to explain the state of a thermodynamic system.

b) reversible process: a reversible process returns the system to its original state without there being a variation in either the system or the external environment.

enthalpy: heat found in a system.

entropy: is the measure of disorder in a system

internal energy: internal energy is the energy that a molecule or atom possesses in a compound.

isentropic process: in thermodynamics is when there is no change in entropy.

adiabatic: when there is no heat change between the system and the surroundings.

Alex Ar [27]3 years ago
5 0

Answer:

State functions are Temperature, Enthalpy, Energy, Internal Energy and Adiabatic work.

Explanation:

a) State functions are those thermodynamic functions which depends only on the final and initial state of the system but not on the path followed.

From the given options only heat is not a state function.

b)  (i) Reversible Process is the process which can be reversed at any point by making even very small changes in the properties of the system.

(ii) Enthalpy is defined as the total heat content of the system. It can also be written as the sum of internal energy and product of pressure and volume of the system.

(iii) Entropy defines the extent of randomness in any system.

So,  a substance in gaseous state has more entropy than its liquid state as gaseous particles can more freely.

(iv) Internal Energy is the energy that involves both potential and kinetic energy of the system. It involves energy for all sorts of random motions of the particles.

(v) Isentropic processes are processes in which entropy remains constant or entropy change is zero during the process.

(vi) Adiabatic processes are those process in which there is no heat change in the process. For example in thermos flask, there is no exchange of heat between system and surroundings.

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The pressure of a sample of helium is 1.556 atm in a 268.5 mL container. If the container is compressed to 112.4 mL without chan
Rainbow [258]

Answer:

a.  3.72 [atm]

Explanation:

For a gas at constant temperature, (with no change in number of molecules of the gas), we can apply Boyle's Law:  P_1V_1=P_2V_2

(1.556[atm])(268.5[mL])=P_2(112.4[mL])

\dfrac{(1.556[atm])(268.5[mL\!\!\!\!\!\!\!\!{--}])}{112.4[mL \!\!\!\!\!\!\!\!{--}]}=\dfrac{P_2(112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----})}{112.4[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{-----}}

3.716957[atm]=P_2

It seems like the answer should have 4 significant figures since all of the other quantities have 4 significant figures, but the closest answer choice of those provided is a.  3.72

3 0
2 years ago
WILL MARK BRANILEST
ahrayia [7]

Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

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3 years ago
A 256 mL sample of HCl gas is in a flask where it exerts a force (pressure) of 67.5 mmHg. What is the pressure of the gas if it
Effectus [21]

Answer:

The pressure in the new flask would be 128\; \rm mmHg if the \rm HCl here acts like an ideal gas.  

Explanation:

Assume that the \rm HCl sample here acts like an ideal gas. By Boyle's Law, the pressure P of the gas should be inversely proportional to its volume V.

For example, let the initial volume and pressure of the sample be V_1 and P_1. The new volume V_2 and pressure P_2 of this sample shall satisfy the equation: P_1 \cdot V_1 =P_2 \cdot V_2.

In this question,

  • The initial volume of the gas is V_1= 256\; \rm mL.
  • The initial pressure of the gas is P_1 = 67.5\; \rm mmHg.
  • The new volume of the gas is V_2 = 135\; \rm mL.

The goal is to find the new pressure of this gas, P_2.

Assume that this sample is indeed an ideal gas. Then the equation P_1 \cdot V_1 =P_2 \cdot V_2 should still hold. Rearrange the equation to separate the unknown, P_2. Note: make sure that the units for V_1 and V_2 are the same before evaluating. That way, the unit of

\begin{aligned} & P_2\\ &= \frac{P_1 \cdot V_1}{V_2} \\ &= \frac{256\; \rm mL \times 67.5\; \rm mmHg}{135\; \rm mL} \\ & \approx 128\; \rm mmHg\end{aligned}.

3 0
3 years ago
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