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IrinaK [193]
3 years ago
12

I am not sure if my son got the first answers right and he is stuck on the last three. The teacher did not provide good instruct

ions. Can anyone help us out? Thank you.

Mathematics
1 answer:
Paul [167]3 years ago
5 0

Answer:

1. Is correct

2. Isn't correct, (It would be number 1)

3. I'm unsure, (But I believe its number 1)

Step-by-step explanation:

2. These are angles across from each other.

3.  These are Angles of the same side that don't over lap.

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329 ten thousandths<br> is how much greater than 32 thousandths
Dennis_Churaev [7]
329 :32=10,28125 is the answer
3 0
3 years ago
Can someone help me please
alekssr [168]
Use the formula x+x+1+x+2 or 3x+3=170 to find x. x is the first number. Then add x+1 to find the second number. Then add x+2 to find the third final number.
x will equal 167/3 which is a decimal, so just plug it in to the 3 equations I mentioned above to find your 3 consecutive numbers. More questions? Just ask me!
4 0
3 years ago
Read 2 more answers
Is 13/12 greater then 6/5?
Anton [14]

Answer:

yes

Step-by-step explanation:

6 0
2 years ago
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Determine the number and types of solutions for<br><br> 6m^2-3m-4=0
Anna11 [10]

Answer:

2 real solutions

Step-by-step explanation:

Remember this messy thing?

x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

The <em>quadratic formula</em>, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the <em>type</em> of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the <em>discriminant</em>. If it's non-negative, we'll have <em>real</em> roots, if it's negative, we'll have <em>complex roots</em>.

For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.

4 0
2 years ago
PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
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